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The maximum number of intensity minima that can be observed in the Fraunhofer diffraction pattern of a single slit (width 10 µm) illuminated by a laser beam (wavelength 0.630 µm) will be?
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The maximum number of intensity minima that can be observed in the Fra...
The maximum number of intensity minima in the Fraunhofer diffraction pattern of a single slit can be calculated using the formula:
n = (2 * a * sin(θ))/λ
Where:
- n is the number of intensity minima
- a is the width of the slit
- θ is the angle of diffraction
- λ is the wavelength of light
Step 1: Calculating the angle of diffraction (θ)
The angle of diffraction can be calculated using the formula:
sin(θ) = λ / (n * a)
where λ is the wavelength of light, n is the order of the minima (for the first minimum, n = 1), and a is the width of the slit.
Step 2: Calculating the maximum number of intensity minima (n)
To find the maximum number of intensity minima, we need to find the maximum value of sin(θ) that satisfies the condition for a valid diffraction pattern. The maximum value of sin(θ) is 1, so we can rearrange the formula as follows:
n = (2 * a * sin(θ))/λ = (2 * a) / λ
Substituting the given values:
a = 10 µm (width of the slit)
λ = 0.630 µm (wavelength of light)
n = (2 * 10 µm) / 0.630 µm = 31.75 ≈ 31
Therefore, the maximum number of intensity minima that can be observed in the Fraunhofer diffraction pattern of a single slit with a width of 10 µm and illuminated by a laser beam with a wavelength of 0.630 µm is approximately 31.
n = (2 * a * sin(θ))/λ
Where:
- n is the number of intensity minima
- a is the width of the slit
- θ is the angle of diffraction
- λ is the wavelength of light
Step 1: Calculating the angle of diffraction (θ)
The angle of diffraction can be calculated using the formula:
sin(θ) = λ / (n * a)
where λ is the wavelength of light, n is the order of the minima (for the first minimum, n = 1), and a is the width of the slit.
Step 2: Calculating the maximum number of intensity minima (n)
To find the maximum number of intensity minima, we need to find the maximum value of sin(θ) that satisfies the condition for a valid diffraction pattern. The maximum value of sin(θ) is 1, so we can rearrange the formula as follows:
n = (2 * a * sin(θ))/λ = (2 * a) / λ
Substituting the given values:
a = 10 µm (width of the slit)
λ = 0.630 µm (wavelength of light)
n = (2 * 10 µm) / 0.630 µm = 31.75 ≈ 31
Therefore, the maximum number of intensity minima that can be observed in the Fraunhofer diffraction pattern of a single slit with a width of 10 µm and illuminated by a laser beam with a wavelength of 0.630 µm is approximately 31.
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The maximum number of intensity minima that can be observed in the Fraunhofer diffraction pattern of a single slit (width 10 µm) illuminated by a laser beam (wavelength 0.630 µm) will be? for Physics 2025 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The maximum number of intensity minima that can be observed in the Fraunhofer diffraction pattern of a single slit (width 10 µm) illuminated by a laser beam (wavelength 0.630 µm) will be? covers all topics & solutions for Physics 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The maximum number of intensity minima that can be observed in the Fraunhofer diffraction pattern of a single slit (width 10 µm) illuminated by a laser beam (wavelength 0.630 µm) will be?.
The maximum number of intensity minima that can be observed in the Fraunhofer diffraction pattern of a single slit (width 10 µm) illuminated by a laser beam (wavelength 0.630 µm) will be? for Physics 2025 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The maximum number of intensity minima that can be observed in the Fraunhofer diffraction pattern of a single slit (width 10 µm) illuminated by a laser beam (wavelength 0.630 µm) will be? covers all topics & solutions for Physics 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The maximum number of intensity minima that can be observed in the Fraunhofer diffraction pattern of a single slit (width 10 µm) illuminated by a laser beam (wavelength 0.630 µm) will be?.
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