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Section 1Q. No. 41- 48 carry 4 marks each.The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusiveQ.Let be a continuous function. For if F(a) + 2 is the area of the region bounded by x = 0, y = 0, y = f (x) and x = a, then f (0) isCorrect answer is '3'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Section 1Q. No. 41- 48 carry 4 marks each.The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusiveQ.Let be a continuous function. For if F(a) + 2 is the area of the region bounded by x = 0, y = 0, y = f (x) and x = a, then f (0) isCorrect answer is '3'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Section 1Q. No. 41- 48 carry 4 marks each.The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusiveQ.Let be a continuous function. For if F(a) + 2 is the area of the region bounded by x = 0, y = 0, y = f (x) and x = a, then f (0) isCorrect answer is '3'. Can you explain this answer?.

Solutions for Section 1Q. No. 41- 48 carry 4 marks each.The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusiveQ.Let be a continuous function. For if F(a) + 2 is the area of the region bounded by x = 0, y = 0, y = f (x) and x = a, then f (0) isCorrect answer is '3'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

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