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In forming a committee of 5 out of 5 males and 6 females how many choices you have to made so that there are 3 males and 2 females? How many choices you have to make if there are 2 males?
- a)150
- b)200
- c)1
- d)461
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In forming a committee of 5 out of 5 males and 6 females how many choi...
Given: 5 males and 6 females
To form a committee of 5 members with 3 males and 2 females, we need to select 3 males out of 5 and 2 females out of 6. We can do this in the following way:
- Selecting 3 males out of 5: 5C3 = 10 ways (using combination formula)
- Selecting 2 females out of 6: 6C2 = 15 ways (using combination formula)
- Total number of ways: 10 x 15 = 150 ways (using multiplication principle)
Therefore, we have 150 choices to make a committee of 5 members with 3 males and 2 females.
To form a committee of 5 members with 2 males and 3 females, we need to select 2 males out of 5 and 3 females out of 6. We can do this in the following way:
- Selecting 2 males out of 5: 5C2 = 10 ways (using combination formula)
- Selecting 3 females out of 6: 6C3 = 20 ways (using combination formula)
- Total number of ways: 10 x 20 = 200 ways (using multiplication principle)
Therefore, we have 200 choices to make a committee of 5 members with 2 males and 3 females.
Hence, the correct answer is option B) 200.
To form a committee of 5 members with 3 males and 2 females, we need to select 3 males out of 5 and 2 females out of 6. We can do this in the following way:
- Selecting 3 males out of 5: 5C3 = 10 ways (using combination formula)
- Selecting 2 females out of 6: 6C2 = 15 ways (using combination formula)
- Total number of ways: 10 x 15 = 150 ways (using multiplication principle)
Therefore, we have 150 choices to make a committee of 5 members with 3 males and 2 females.
To form a committee of 5 members with 2 males and 3 females, we need to select 2 males out of 5 and 3 females out of 6. We can do this in the following way:
- Selecting 2 males out of 5: 5C2 = 10 ways (using combination formula)
- Selecting 3 females out of 6: 6C3 = 20 ways (using combination formula)
- Total number of ways: 10 x 20 = 200 ways (using multiplication principle)
Therefore, we have 200 choices to make a committee of 5 members with 2 males and 3 females.
Hence, the correct answer is option B) 200.
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In forming a committee of 5 out of 5 males and 6 females how many choi...
Correct answer is b
How many choices you have to make if there are 2 males? ignore it is for confusion
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In forming a committee of 5 out of 5 males and 6 females how many choices you have to made so that there are 3 males and 2 females? How many choices you have to make if there are 2 males?a)150b)200c)1d)461Correct answer is option 'B'. Can you explain this answer?
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