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What is the area of the quadrilateral formed by the solution set of the inequations 5x + 7y < 42, x > 0, y > 0 and x <  5?
  • a)
    19 sq. units
  • b)
    18.4 sq. units
  • c)
    25.6 sq. units
  • d)
    21 sq. units
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
What is the area of the quadrilateral formed by the solution set of th...
Solution: The region formed by using the given inequations is
By solving equations 5x + 7y = 42, x = 0, y = 0 and x = 5, we get the intersection points. We can figure out that the shaded region is a trapezium.
The lengths of the parallel sides are 6 and 2.4 and the height is equal to 5 units.
∴ Required area = 1/2 x (sum of parallel sides) x height
= 1/2 x (6 + 2.4) x 5
= 21
The required area is 21 sq. units.
Hence, option 4.
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What is the area of the quadrilateral formed by the solution set of the inequations 5x + 7y < 42, x > 0, y >0 and x < 5?a)19 sq. unitsb)18.4 sq. unitsc)25.6 sq. unitsd)21 sq. unitsCorrect answer is option 'D'. Can you explain this answer?
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