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The plot shows the variation of −ln Kp versus temperature for the two reactions.andIdentify the correct statement :a)At T>1200 K, carbon will reduce MO(s) to M(s)b)At T<1200 K, the reactionMO(s) + C(s) → M(s) + CO(g) is spontaneous.c)At T<1200 K, oxidation of carbon is unfavourable.d)Oxidation of carbon is favourable at all temperatures.Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The plot shows the variation of −ln Kp versus temperature for the two reactions.andIdentify the correct statement :a)At T>1200 K, carbon will reduce MO(s) to M(s)b)At T<1200 K, the reactionMO(s) + C(s) → M(s) + CO(g) is spontaneous.c)At T<1200 K, oxidation of carbon is unfavourable.d)Oxidation of carbon is favourable at all temperatures.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The plot shows the variation of −ln Kp versus temperature for the two reactions.andIdentify the correct statement :a)At T>1200 K, carbon will reduce MO(s) to M(s)b)At T<1200 K, the reactionMO(s) + C(s) → M(s) + CO(g) is spontaneous.c)At T<1200 K, oxidation of carbon is unfavourable.d)Oxidation of carbon is favourable at all temperatures.Correct answer is option 'D'. Can you explain this answer?.

Solutions for The plot shows the variation of −ln Kp versus temperature for the two reactions.andIdentify the correct statement :a)At T>1200 K, carbon will reduce MO(s) to M(s)b)At T<1200 K, the reactionMO(s) + C(s) → M(s) + CO(g) is spontaneous.c)At T<1200 K, oxidation of carbon is unfavourable.d)Oxidation of carbon is favourable at all temperatures.Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of The plot shows the variation of −ln Kp versus temperature for the two reactions.andIdentify the correct statement :a)At T>1200 K, carbon will reduce MO(s) to M(s)b)At T<1200 K, the reactionMO(s) + C(s) → M(s) + CO(g) is spontaneous.c)At T<1200 K, oxidation of carbon is unfavourable.d)Oxidation of carbon is favourable at all temperatures.Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The plot shows the variation of −ln Kp versus temperature for the two reactions.andIdentify the correct statement :a)At T>1200 K, carbon will reduce MO(s) to M(s)b)At T<1200 K, the reactionMO(s) + C(s) → M(s) + CO(g) is spontaneous.c)At T<1200 K, oxidation of carbon is unfavourable.d)Oxidation of carbon is favourable at all temperatures.Correct answer is option 'D'. Can you explain this answer?, a detailed solution for The plot shows the variation of −ln Kp versus temperature for the two reactions.andIdentify the correct statement :a)At T>1200 K, carbon will reduce MO(s) to M(s)b)At T<1200 K, the reactionMO(s) + C(s) → M(s) + CO(g) is spontaneous.c)At T<1200 K, oxidation of carbon is unfavourable.d)Oxidation of carbon is favourable at all temperatures.Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of The plot shows the variation of −ln Kp versus temperature for the two reactions.andIdentify the correct statement :a)At T>1200 K, carbon will reduce MO(s) to M(s)b)At T<1200 K, the reactionMO(s) + C(s) → M(s) + CO(g) is spontaneous.c)At T<1200 K, oxidation of carbon is unfavourable.d)Oxidation of carbon is favourable at all temperatures.Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The plot shows the variation of −ln Kp versus temperature for the two reactions.andIdentify the correct statement :a)At T>1200 K, carbon will reduce MO(s) to M(s)b)At T<1200 K, the reactionMO(s) + C(s) → M(s) + CO(g) is spontaneous.c)At T<1200 K, oxidation of carbon is unfavourable.d)Oxidation of carbon is favourable at all temperatures.Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.