A overhanging beam of ABC loaded as shown in figure. Determine the def...
Problem Statement: Determine the deflection at point C of an overhanging beam of ABC loaded as shown in figure. Take E=2x105 N/mm2 and I=5x108 mm2.
Solution:Step 1: Draw the free body diagram of the beam and determine the reactions at A and B.
∑MA=0: -RA x 500 + 90 x 300 + 80 x 600 = 0
RA = 108 kN
∑Fy=0: RA + RB - 90 - 80 = 0
RB = 62 kN
Step 2: Determine the equation of the deflection curve.
Using double integration method, the equation of the deflection curve is given by:
y(x) = (wx/24EI) [x
3 - 2Lx
2 + (L
2 - 4x
2)]
where, w = load per unit length = (90 + 80)/600 = 0.25 kN/mm
L = length of the beam between A and B = 600 mm
Step 3: Determine the deflection at point C.
Substituting x = 900 mm in the equation of the deflection curve, we get:
y(900) = (0.25 x 900/24 x 2 x 10
5 x 5 x 10
8) [(900)
3 - 2 x 600 x (900)
2 + (600
2 - 4 x 900
2)]
y(900) = -0.83 mm (approx.)
Therefore, the deflection at point C is -0.83 mm.
Conclusion: The deflection at point C of