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A clean tube of internal diameter 3 mm is immersed in a liquid with a coefficient of surface tension 0.48 N/m. The angle of contact of the liquid with the glass can be assumed to be 130º. The density of the liquid is 13,600 kg/m3 . What would be the level of the liquid in tube relative to the free surface of the liquid outside the tube.?
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A clean tube of internal diameter 3 mm is immersed in a liquid with a ...
Calculation of the level of liquid in the tube


Determination of the contact angle


The contact angle of the liquid with the glass can be assumed to be 130º.


Determination of the coefficient of capillary rise


The coefficient of capillary rise can be calculated using the formula:


\(\frac{2σcosθ}{ρgr}\)


Where:


  • σ = Coefficient of surface tension (0.48 N/m)

  • θ = Contact angle (130º)

  • ρ = Density of the liquid (13,600 kg/m3)

  • g = Acceleration due to gravity (9.81 m/s2)

  • r = Internal radius of the tube (1.5 mm or 0.0015 m)



Substituting the given values, we get:


\(\frac{2×0.48×cos(130º)}{13600×9.81×0.0015}\)


On solving the above equation, we get:


h = 0.228 mm


Determination of the level of liquid in the tube


The level of liquid in the tube can be calculated using the formula:


h = \(\frac{ρgh}{σcosθ}\)


Where:


  • h = Level of liquid in the tube

  • ρ = Density of the liquid (13,600 kg/m3)

  • g = Acceleration due to gravity (9.81 m/s2)

  • σ = Coefficient of surface tension (0.48 N/m)

  • θ = Contact angle (130º)



Substituting the given values, we get:


h = \(\frac{13600×9.81×0.228×10^-3}{0.48×cos(130º)}\)


On solving the above equation, we get:


h = 0.165 mm


Conclusion


The level of the liquid in the tube relative to the free surface of the liquid outside the tube is 0.165 mm.
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A clean tube of internal diameter 3 mm is immersed in a liquid with a coefficient of surface tension 0.48 N/m. The angle of contact of the liquid with the glass can be assumed to be 130º. The density of the liquid is 13,600 kg/m3 . What would be the level of the liquid in tube relative to the free surface of the liquid outside the tube.?
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A clean tube of internal diameter 3 mm is immersed in a liquid with a coefficient of surface tension 0.48 N/m. The angle of contact of the liquid with the glass can be assumed to be 130º. The density of the liquid is 13,600 kg/m3 . What would be the level of the liquid in tube relative to the free surface of the liquid outside the tube.? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A clean tube of internal diameter 3 mm is immersed in a liquid with a coefficient of surface tension 0.48 N/m. The angle of contact of the liquid with the glass can be assumed to be 130º. The density of the liquid is 13,600 kg/m3 . What would be the level of the liquid in tube relative to the free surface of the liquid outside the tube.? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A clean tube of internal diameter 3 mm is immersed in a liquid with a coefficient of surface tension 0.48 N/m. The angle of contact of the liquid with the glass can be assumed to be 130º. The density of the liquid is 13,600 kg/m3 . What would be the level of the liquid in tube relative to the free surface of the liquid outside the tube.?.
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