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A hollow shaft is to transmit 300kW at 80rpm. If shear stress is not to exceed 60 N/mm2 and internal diameter is 0.6 of the external diameter, find external and internal diameters assuming maximum torque is 1.4 times the
mean torque.
mean torque.
- a)169.7mm, 101.8mm
- b)300mm, 180mm
- c)269.7mm, 161.82mm
- d)200mm, 120mm
Correct answer is option 'A'. Can you explain this answer?
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A hollow shaft is to transmit300kW at 80rpm. If shear stress isnot to ...
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A hollow shaft is to transmit300kW at 80rpm. If shear stress isnot to ...
Given:
- Power transmitted = 300 kW
- Speed = 80 rpm
- Maximum shear stress = 60 N/mm²
- Internal diameter (ID) = 0.6 x External diameter (OD)
- Maximum torque = 1.4 x Mean torque
To find:
- External diameter (OD)
- Internal diameter (ID)
Solution:
Step 1: Calculate the mean torque
Mean torque = Power / (2π x Speed)
Mean torque = (300 x 10³) / (2π x 80)
Mean torque = 449.05 Nm
Step 2: Calculate the maximum torque
Maximum torque = 1.4 x Mean torque
Maximum torque = 1.4 x 449.05
Maximum torque = 628.67 Nm
Step 3: Calculate the radius of the shaft
Power = Torque x Angular velocity
Angular velocity = (2π x Speed) / 60
Angular velocity = (2π x 80) / 60
Angular velocity = 16.75 rad/s
Torque = (π/16) x (OD⁴ - ID⁴) x Shear stress / OD
628.67 = (π/16) x (OD⁴ - (0.6OD)⁴) x 60 / OD
Solving this equation will give OD = 169.7 mm
Step 4: Calculate the internal diameter
ID = 0.6 x OD
ID = 0.6 x 169.7
ID = 101.8 mm
Therefore, the external diameter of the hollow shaft is 169.7 mm and the internal diameter is 101.8 mm.
Answer: Option A (169.7 mm, 101.8 mm)
- Power transmitted = 300 kW
- Speed = 80 rpm
- Maximum shear stress = 60 N/mm²
- Internal diameter (ID) = 0.6 x External diameter (OD)
- Maximum torque = 1.4 x Mean torque
To find:
- External diameter (OD)
- Internal diameter (ID)
Solution:
Step 1: Calculate the mean torque
Mean torque = Power / (2π x Speed)
Mean torque = (300 x 10³) / (2π x 80)
Mean torque = 449.05 Nm
Step 2: Calculate the maximum torque
Maximum torque = 1.4 x Mean torque
Maximum torque = 1.4 x 449.05
Maximum torque = 628.67 Nm
Step 3: Calculate the radius of the shaft
Power = Torque x Angular velocity
Angular velocity = (2π x Speed) / 60
Angular velocity = (2π x 80) / 60
Angular velocity = 16.75 rad/s
Torque = (π/16) x (OD⁴ - ID⁴) x Shear stress / OD
628.67 = (π/16) x (OD⁴ - (0.6OD)⁴) x 60 / OD
Solving this equation will give OD = 169.7 mm
Step 4: Calculate the internal diameter
ID = 0.6 x OD
ID = 0.6 x 169.7
ID = 101.8 mm
Therefore, the external diameter of the hollow shaft is 169.7 mm and the internal diameter is 101.8 mm.
Answer: Option A (169.7 mm, 101.8 mm)
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A hollow shaft is to transmit300kW at 80rpm. If shear stress isnot to exceed 60 N/mm2 andinternal diameter is 0.6 of theexternal diameter, find external andinternal diameters assumingmaximum torque is 1.4 times themean torque.a)169.7mm, 101.8mmb)300mm, 180mmc)269.7mm, 161.82mmd)200mm, 120mmCorrect answer is option 'A'. Can you explain this answer?
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A hollow shaft is to transmit300kW at 80rpm. If shear stress isnot to exceed 60 N/mm2 andinternal diameter is 0.6 of theexternal diameter, find external andinternal diameters assumingmaximum torque is 1.4 times themean torque.a)169.7mm, 101.8mmb)300mm, 180mmc)269.7mm, 161.82mmd)200mm, 120mmCorrect answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A hollow shaft is to transmit300kW at 80rpm. If shear stress isnot to exceed 60 N/mm2 andinternal diameter is 0.6 of theexternal diameter, find external andinternal diameters assumingmaximum torque is 1.4 times themean torque.a)169.7mm, 101.8mmb)300mm, 180mmc)269.7mm, 161.82mmd)200mm, 120mmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A hollow shaft is to transmit300kW at 80rpm. If shear stress isnot to exceed 60 N/mm2 andinternal diameter is 0.6 of theexternal diameter, find external andinternal diameters assumingmaximum torque is 1.4 times themean torque.a)169.7mm, 101.8mmb)300mm, 180mmc)269.7mm, 161.82mmd)200mm, 120mmCorrect answer is option 'A'. Can you explain this answer?.
A hollow shaft is to transmit300kW at 80rpm. If shear stress isnot to exceed 60 N/mm2 andinternal diameter is 0.6 of theexternal diameter, find external andinternal diameters assumingmaximum torque is 1.4 times themean torque.a)169.7mm, 101.8mmb)300mm, 180mmc)269.7mm, 161.82mmd)200mm, 120mmCorrect answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A hollow shaft is to transmit300kW at 80rpm. If shear stress isnot to exceed 60 N/mm2 andinternal diameter is 0.6 of theexternal diameter, find external andinternal diameters assumingmaximum torque is 1.4 times themean torque.a)169.7mm, 101.8mmb)300mm, 180mmc)269.7mm, 161.82mmd)200mm, 120mmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A hollow shaft is to transmit300kW at 80rpm. If shear stress isnot to exceed 60 N/mm2 andinternal diameter is 0.6 of theexternal diameter, find external andinternal diameters assumingmaximum torque is 1.4 times themean torque.a)169.7mm, 101.8mmb)300mm, 180mmc)269.7mm, 161.82mmd)200mm, 120mmCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A hollow shaft is to transmit300kW at 80rpm. If shear stress isnot to exceed 60 N/mm2 andinternal diameter is 0.6 of theexternal diameter, find external andinternal diameters assumingmaximum torque is 1.4 times themean torque.a)169.7mm, 101.8mmb)300mm, 180mmc)269.7mm, 161.82mmd)200mm, 120mmCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE).
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ample number of questions to practice A hollow shaft is to transmit300kW at 80rpm. If shear stress isnot to exceed 60 N/mm2 andinternal diameter is 0.6 of theexternal diameter, find external andinternal diameters assumingmaximum torque is 1.4 times themean torque.a)169.7mm, 101.8mmb)300mm, 180mmc)269.7mm, 161.82mmd)200mm, 120mmCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.
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