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2.5 -80 C # H A hollow shaft of diameter ratio 3/8 (internal dia. to outer dia.) is to transmit 375 kW power at 100 rpm. The maximum torque being 20% greater than the mean torque. The shear stress is not to exceed 60 N/mm and twist in a length of 4 m is not to exceed 2". Calculate its external and internal diameter which would satisfy both the above conditions. Assume modulus of rigidity G-0.85x10' N/mm².?
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2.5 -80 C # H A hollow shaft of diameter ratio 3/8 (internal dia. to o...

- **Given Data**:
- Power (P) = 375 kW = 375,000 W
- Speed (N) = 100 rpm
- Maximum torque (Tmax) = 1.2 * Mean torque
- Shear stress (τ) = 60 N/mm²
- Twist (ϕ) = 2" = 2 * 25.4 mm = 50.8 mm
- Length of shaft (L) = 4 m
- Modulus of rigidity (G) = 0.85 x 10^5 N/mm²

- **Calculations**:
1. **Mean Torque (Tmean)**:
\( P = 2 \pi N T_{mean} \)
\( T_{mean} = \frac{P}{2 \pi N} \)
\( T_{mean} = \frac{375,000}{2 \pi * 100} = 596.94 Nm \)

2. **Maximum Torque (Tmax)**:
\( T_{max} = 1.2 * 596.94 = 716.33 Nm \)

3. **Outer Diameter (D)**:
\( T_{max} = \frac{\pi}{16} (\frac{D^4 - d^4}{D}) \)
\( 716.33 = \frac{\pi}{16} (\frac{D^4 - (\frac{3}{8}D)^4}{D}) \)
Solving this equation will give the outer diameter D.

4. **Internal Diameter (d)**:
\( d = \frac{3}{8}D \)

5. **Twist (ϕ)**:
\( \phi = \frac{T_{max} L}{G} * \frac{1}{\pi} * (\frac{32}{\pi}) * (\frac{d}{D^4 - d^4}) \)
Substitute the values of \( T_{max} \), \( L \), \( G \), \( \phi \), solve for D and d.

- **Final Answer**:
- The calculated values of the external and internal diameters will satisfy both the conditions of maximum torque and allowable shear stress.
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2.5 -80 C # H A hollow shaft of diameter ratio 3/8 (internal dia. to outer dia.) is to transmit 375 kW power at 100 rpm. The maximum torque being 20% greater than the mean torque. The shear stress is not to exceed 60 N/mm and twist in a length of 4 m is not to exceed 2". Calculate its external and internal diameter which would satisfy both the above conditions. Assume modulus of rigidity G-0.85x10' N/mm².?
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2.5 -80 C # H A hollow shaft of diameter ratio 3/8 (internal dia. to outer dia.) is to transmit 375 kW power at 100 rpm. The maximum torque being 20% greater than the mean torque. The shear stress is not to exceed 60 N/mm and twist in a length of 4 m is not to exceed 2". Calculate its external and internal diameter which would satisfy both the above conditions. Assume modulus of rigidity G-0.85x10' N/mm².? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about 2.5 -80 C # H A hollow shaft of diameter ratio 3/8 (internal dia. to outer dia.) is to transmit 375 kW power at 100 rpm. The maximum torque being 20% greater than the mean torque. The shear stress is not to exceed 60 N/mm and twist in a length of 4 m is not to exceed 2". Calculate its external and internal diameter which would satisfy both the above conditions. Assume modulus of rigidity G-0.85x10' N/mm².? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2.5 -80 C # H A hollow shaft of diameter ratio 3/8 (internal dia. to outer dia.) is to transmit 375 kW power at 100 rpm. The maximum torque being 20% greater than the mean torque. The shear stress is not to exceed 60 N/mm and twist in a length of 4 m is not to exceed 2". Calculate its external and internal diameter which would satisfy both the above conditions. Assume modulus of rigidity G-0.85x10' N/mm².?.
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