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A hollow circular column of internal diameter 'd' and external diameter '1.5 d’ is subjected to compressive load. The maximum distance of the point of application of load from the centre for no tension is
  • a)
    d/8
  • b)
    13d/48
  • c)
    d/4
  • d)
    13d/96
Correct answer is option 'B'. Can you explain this answer?
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Assuming that the column has a uniform thickness and is made of a homogeneous material, we can use the following formula to calculate its cross-sectional area:

A = π/4 * (D^2 - d^2)

where A is the area, D is the external diameter, and d is the internal diameter.

Substituting the given values, we get:

A = π/4 * ((1.5d)^2 - d^2)
= π/4 * (2.25d^2 - d^2)
= π/4 * 1.25d^2
= 0.9817d^2 (rounded to four decimal places)

Therefore, the cross-sectional area of the column is approximately 0.9817 times the square of the internal diameter.
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