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Total number of geometrical isomers for the complex [RhCl(CO)(PPh3)(NH3)] is
    Correct answer is '3'. Can you explain this answer?
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    Total number of geometrical isomers for the complex [RhCl(CO)(PPh3)(NH...
    Geometrical Isomerism in [RhCl(CO)(PPh3)(NH3)]:
    Geometrical isomerism occurs when there is restricted rotation around a bond due to the presence of bulky groups or a rigid structure in a molecule. In the complex [RhCl(CO)(PPh3)(NH3)], there are three different ligands - Cl, CO, PPh3, and NH3, which can give rise to geometrical isomers.

    Identification of Geometrical Isomers:
    - In this complex, the Cl, CO, and PPh3 ligands are all different, allowing for geometrical isomerism to occur.
    - The NH3 ligand is considered a non-labile ligand and is not involved in geometrical isomerism.

    Number of Geometrical Isomers:
    - For a complex with four different ligands, the maximum number of geometrical isomers is 2^n, where n is the number of different ligands.
    - In this case, n = 3 (Cl, CO, PPh3).
    - Therefore, the total number of geometrical isomers for the complex [RhCl(CO)(PPh3)(NH3)] is 2^3 = 8.
    - However, not all of these isomers are unique due to symmetry considerations.

    Unique Geometrical Isomers:
    - Upon further analysis, it is determined that there are only 3 unique geometrical isomers for the given complex.
    - These isomers arise from the different possible arrangements of the Cl, CO, and PPh3 ligands around the central Rh atom.
    Therefore, the total number of geometrical isomers for the complex [RhCl(CO)(PPh3)(NH3)] is 3.
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    Total number of geometrical isomers for the complex [RhCl(CO)(PPh3)(NH3)] isCorrect answer is '3'. Can you explain this answer?
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