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An undisturbed soil sample has a plastic limit of 25%, a natural moisture content of 40% and liquidity index of 50%, Its liquid limit in % will be

  • a)
    50

  • b)
    55

  • c)
    60

  • d)
    75

Correct answer is option 'B'. Can you explain this answer?
Verified Answer
An undisturbed soil sample has a plastic limit of 25%, a natural moist...
The formula for liquidity index is given as follows where w is the natural moisture content, wp is the plastic limit, Ip is the liquid limit. So we can calculate the liquid limit by substituting the values.






⇒ Ip = 30%

Also Ip = wl - wp

⇒ Wl = 30 + 25 = 55%
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Most Upvoted Answer
An undisturbed soil sample has a plastic limit of 25%, a natural moist...
Given data:
Plastic limit (PL) = 25%
Natural moisture content (w) = 40%
Liquidity index (LI) = 50%

To find: Liquid limit (LL)

Formula used:
Liquidity index (LI) = (w - PL) / (LL - PL) × 100

Calculation:
Substituting the given values in the above formula, we get:
50 = (40 - 25) / (LL - 25) × 100

⇒ (LL - 25) / 100 = 15 / 50

⇒ LL - 25 = 0.3 × 100

⇒ LL = 25 + 30

⇒ LL = 55%

Therefore, the liquid limit of the soil sample is 55%.

Hence, option (b) is the correct answer.
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An undisturbed soil sample has a plastic limit of 25%, a natural moisture content of 40% and liquidity index of 50%, Its liquid limit in % will bea)50b)55c)60d)75Correct answer is option 'B'. Can you explain this answer?
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