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The sequent depth ratio in a. hydraulic jump formed in a horizontal rectangular channel is 16.48. The Froude number of the supercritical stream is
- a)4.0
- b)8.0
- c)12.0
- d)120
Correct answer is option 'C'. Can you explain this answer?
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Given: Sequent depth ratio = 16.48
We know that the sequent depth ratio is given by the formula:
Sequent depth ratio = (y2/y1) = (1 + (8/3)*Fr1^2)^(1/2)
where,
y1 = upstream depth of flow
y2 = downstream depth of flow
Fr1 = Froude number at upstream section
Assuming y2 = y1/2 (for hydraulic jump in rectangular channel), we can rewrite the above equation as:
16.48 = (y2/y1) = (1 + (8/3)*Fr1^2)^(1/2)
Squaring both sides, we get:
(16.48)^2 = 1 + (8/3)*Fr1^2
Fr1^2 = ((16.48)^2 - 1) * (3/8)
Fr1 = 12.0 (approx)
Therefore, the Froude number of the supercritical stream is 12.0. Hence, option (c) is the correct answer.
We know that the sequent depth ratio is given by the formula:
Sequent depth ratio = (y2/y1) = (1 + (8/3)*Fr1^2)^(1/2)
where,
y1 = upstream depth of flow
y2 = downstream depth of flow
Fr1 = Froude number at upstream section
Assuming y2 = y1/2 (for hydraulic jump in rectangular channel), we can rewrite the above equation as:
16.48 = (y2/y1) = (1 + (8/3)*Fr1^2)^(1/2)
Squaring both sides, we get:
(16.48)^2 = 1 + (8/3)*Fr1^2
Fr1^2 = ((16.48)^2 - 1) * (3/8)
Fr1 = 12.0 (approx)
Therefore, the Froude number of the supercritical stream is 12.0. Hence, option (c) is the correct answer.
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The sequent depth ratio in a. hydraulic jump formed in a horizontal rectangular channel is 16.48. The Froude number of the supercritical stream isa)4.0b)8.0c)12.0d)120Correct answer is option 'C'. Can you explain this answer?
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