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The pair of linear equations x + 2y = 5, 3x + 12y = 10 has –
  • a)
    Unique solution
  • b)
    No solution
  • c)
    More than two solutions
  • d)
    Infinitely many solutions
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The pair of linear equations x + 2y = 5, 3x + 12y = 10 has –a)Un...
Community Answer
The pair of linear equations x + 2y = 5, 3x + 12y = 10 has –a)Un...
No solution.

To see why, let's first put the equations in standard form:

x - 2y = 5

3x - 12y = 10

Now we can use elimination to try to solve for x and y. Let's multiply the first equation by 3 to get rid of the x coefficient:

3x - 6y = 15

3x - 12y = 10

Now we can subtract the first equation from the second:

0x - 6y = -5

Simplifying, we get:

y = 5/6

But if we try to substitute this value of y into the first equation, we get:

x - 2(5/6) = 5

x - 5/3 = 5

x = 20/3

However, if we substitute these values of x and y into the second equation, we get:

3(20/3) - 12(5/6) = 10

20 - 10 = 10

This is a contradiction, since we started with two equations that were supposed to be true at the same time. Therefore, there is no solution to this system of equations.
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