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When A,B and C are deployed for a task, A and B together do 70% of the work and B and C together do 50% of the work. Who is most efficient?
- a)A
- b)B
- c)C
- d)Can't be determined
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
When A,B and C are deployed for a task, A and B together do 70% of the...
A + B = 70%
B + C = 50%
⇒ B = 20% , A = 50% and C = 30%
Hence, A is most efficient.
B + C = 50%
⇒ B = 20% , A = 50% and C = 30%
Hence, A is most efficient.
Most Upvoted Answer
When A,B and C are deployed for a task, A and B together do 70% of the...
Solution:
Let the total work be 100 units.
A and B together do 70% of the work, which is 70 units.
B and C together do 50% of the work, which is 50 units.
Let the work done by A be x units.
Then, the work done by B will be (70 - x) units.
Also, the work done by C will be (50 - (70 - x)) = (x - 20) units.
Therefore, we can write:
x + (70 - x) = 70 (since A and B together do 70% of the work)
x + (x - 20) = 50 (since B and C together do 50% of the work)
Solving the above equations, we get:
x = 40
Therefore, the work done by A is 40 units, and the work done by B is (70 - x) = 30 units.
Hence, the efficiency of A is (40/40) = 1, and the efficiency of B is (30/40) = 0.75.
Similarly, the efficiency of C can be calculated as:
Efficiency of C = (x - 20)/50 = (40 - 20)/50 = 0.4
Therefore, the most efficient worker is A, with an efficiency of 1.
Let the total work be 100 units.
A and B together do 70% of the work, which is 70 units.
B and C together do 50% of the work, which is 50 units.
Let the work done by A be x units.
Then, the work done by B will be (70 - x) units.
Also, the work done by C will be (50 - (70 - x)) = (x - 20) units.
Therefore, we can write:
x + (70 - x) = 70 (since A and B together do 70% of the work)
x + (x - 20) = 50 (since B and C together do 50% of the work)
Solving the above equations, we get:
x = 40
Therefore, the work done by A is 40 units, and the work done by B is (70 - x) = 30 units.
Hence, the efficiency of A is (40/40) = 1, and the efficiency of B is (30/40) = 0.75.
Similarly, the efficiency of C can be calculated as:
Efficiency of C = (x - 20)/50 = (40 - 20)/50 = 0.4
Therefore, the most efficient worker is A, with an efficiency of 1.
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When A,B and C are deployed for a task, A and B together do 70% of the work and B and C together do 50% of the work. Who is most efficient?a)Ab)Bc)Cd)Cant be determinedCorrect answer is option 'A'. Can you explain this answer? for CAT 2025 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about When A,B and C are deployed for a task, A and B together do 70% of the work and B and C together do 50% of the work. Who is most efficient?a)Ab)Bc)Cd)Cant be determinedCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for CAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When A,B and C are deployed for a task, A and B together do 70% of the work and B and C together do 50% of the work. Who is most efficient?a)Ab)Bc)Cd)Cant be determinedCorrect answer is option 'A'. Can you explain this answer?.
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