A man, a woman and a girl worked for a contractor for the same period....
Efficiency of a man : woman : girl = 6 : 3 : 1
∴ Share of a woman and girl =
=
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A man, a woman and a girl worked for a contractor for the same period....
Given information:
- A man is twice as efficient as a woman.
- A woman is thrice as efficient as a girl.
- All three of them worked for the same period.
- They received a total of 10,000 units of money.
Let's assume that the efficiency of the girl is x units of work per day.
- The efficiency of the woman would be 3x units of work per day.
- The efficiency of the man would be twice the efficiency of the woman, which is 2 * 3x = 6x units of work per day.
Let's assume that they worked for 'n' days.
- Therefore, the total work done by the girl would be x * n units.
- The total work done by the woman would be 3x * n units.
- The total work done by the man would be 6x * n units.
Since they all worked for the same period, we can assume that the total work done is the same for all three of them. Therefore, we can equate the total work done and solve for 'n':
x * n + 3x * n + 6x * n = total work done
By simplifying the equation, we get:
10x * n = total work done
Now, let's find the ratio of the work done by the woman and the girl:
- The work done by the woman is 3x * n units.
- The work done by the girl is x * n units.
- Therefore, the ratio of the work done by the woman to the girl is 3x * n / x * n = 3.
Since the total amount of money received by all three of them is 10,000 units, we can use the ratio of their work done to find the amount received by the woman and the girl:
Total amount received by the woman and the girl = (Amount received by the woman + Amount received by the girl) = 10,000 * (3 / (3 + 1)) = 10,000 * (3/4) = 7,500 units.
Therefore, the sum of money received by the woman and the girl together is 7,500 units.
Hence, the correct answer is option 'C' (4000 units).