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A transistor is used in common emitter mode in an amplifier circuit. When a signal of 30 mV is added to the base emitter voltage, the base current changes by 30 μA and collector current by 3 mA. The load resistance is 5 kΩ. The value of transconductance and voltage gain is given bya)gm = 0.10 A/V and AV= 1000b)gm = 0.25 A/V and AV = 250c)gm = 0.10 A/V and AV= 500d)gm = 0.20 A/Vand AV= 750Correct answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared
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the Electrical Engineering (EE) exam syllabus. Information about A transistor is used in common emitter mode in an amplifier circuit. When a signal of 30 mV is added to the base emitter voltage, the base current changes by 30 μA and collector current by 3 mA. The load resistance is 5 kΩ. The value of transconductance and voltage gain is given bya)gm = 0.10 A/V and AV= 1000b)gm = 0.25 A/V and AV = 250c)gm = 0.10 A/V and AV= 500d)gm = 0.20 A/Vand AV= 750Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for A transistor is used in common emitter mode in an amplifier circuit. When a signal of 30 mV is added to the base emitter voltage, the base current changes by 30 μA and collector current by 3 mA. The load resistance is 5 kΩ. The value of transconductance and voltage gain is given bya)gm = 0.10 A/V and AV= 1000b)gm = 0.25 A/V and AV = 250c)gm = 0.10 A/V and AV= 500d)gm = 0.20 A/Vand AV= 750Correct answer is option 'C'. Can you explain this answer?.
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Here you can find the meaning of A transistor is used in common emitter mode in an amplifier circuit. When a signal of 30 mV is added to the base emitter voltage, the base current changes by 30 μA and collector current by 3 mA. The load resistance is 5 kΩ. The value of transconductance and voltage gain is given bya)gm = 0.10 A/V and AV= 1000b)gm = 0.25 A/V and AV = 250c)gm = 0.10 A/V and AV= 500d)gm = 0.20 A/Vand AV= 750Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A transistor is used in common emitter mode in an amplifier circuit. When a signal of 30 mV is added to the base emitter voltage, the base current changes by 30 μA and collector current by 3 mA. The load resistance is 5 kΩ. The value of transconductance and voltage gain is given bya)gm = 0.10 A/V and AV= 1000b)gm = 0.25 A/V and AV = 250c)gm = 0.10 A/V and AV= 500d)gm = 0.20 A/Vand AV= 750Correct answer is option 'C'. Can you explain this answer?, a detailed solution for A transistor is used in common emitter mode in an amplifier circuit. When a signal of 30 mV is added to the base emitter voltage, the base current changes by 30 μA and collector current by 3 mA. The load resistance is 5 kΩ. The value of transconductance and voltage gain is given bya)gm = 0.10 A/V and AV= 1000b)gm = 0.25 A/V and AV = 250c)gm = 0.10 A/V and AV= 500d)gm = 0.20 A/Vand AV= 750Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of A transistor is used in common emitter mode in an amplifier circuit. When a signal of 30 mV is added to the base emitter voltage, the base current changes by 30 μA and collector current by 3 mA. The load resistance is 5 kΩ. The value of transconductance and voltage gain is given bya)gm = 0.10 A/V and AV= 1000b)gm = 0.25 A/V and AV = 250c)gm = 0.10 A/V and AV= 500d)gm = 0.20 A/Vand AV= 750Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A transistor is used in common emitter mode in an amplifier circuit. When a signal of 30 mV is added to the base emitter voltage, the base current changes by 30 μA and collector current by 3 mA. The load resistance is 5 kΩ. The value of transconductance and voltage gain is given bya)gm = 0.10 A/V and AV= 1000b)gm = 0.25 A/V and AV = 250c)gm = 0.10 A/V and AV= 500d)gm = 0.20 A/Vand AV= 750Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.