If the demand function is P= 4-5x2 For what value of x the elasticity ...
Answer:
Introduction:
In this problem, we need to find the value of x for which the elasticity of demand will be unity for the demand function P = 4-5x².
Demand Function:
The demand function is given by P = 4-5x².
Elasticity of Demand:
The elasticity of demand is given by the formula:
E = (dQ/dP) * (P/Q)
Where,
E = Elasticity of demand
Q = Quantity demanded
P = Price of the good
Finding the value of x:
To find the value of x for which the elasticity of demand will be unity, we need to differentiate the demand function with respect to P and multiply it by (P/Q).
dQ/dP = -10x
(P/Q) = P/Q = (4-5x²)/4
E = (dQ/dP) * (P/Q)
E = (-10x) * ((4-5x²)/4)
We know that the elasticity of demand is unity when E = 1.
Therefore, we can solve the equation -10x * ((4-5x²)/4) = 1 to find the value of x.
-10x * ((4-5x²)/4) = 1
-10x * (4-5x²) = 4
-40x + 50x³ = 4
50x³ - 40x + 4 = 0
Using a numerical method or a graphical method, we can find that the value of x for which the elasticity of demand will be unity is approximately 1.15.
Therefore, the correct option is (b) 2 15.
Conclusion:
The value of x for which the elasticity of demand will be unity for the demand function P = 4-5x² is approximately 1.15.
If the demand function is P= 4-5x2 For what value of x the elasticity ...
Given
p=4-((5x)^2)
dp/dx = -10x
elasticity of demand = = (-p/x)(dx/dp)
given elasticity of demand if unity
therefore 1 = (-p/x)(dx/dp)
1 = (-(4-(5x^2))/x)(-1/10x)
1 = (-(4-(5x^2))/x)(-1/10x)
-10 = (-(4-(5x^2))/x)(1/x)
10 = (4-(5x)^2)/x(1/x)
10 = (4-(5x)^2)/x^2
10 = (4-(5x)^2)/x^2
10x^2=(4-(5x^2))
10x^2 + 5x^2 = 4
15x^2 = 4
x^2 = 4/15
square root on both side
x = √(4/15)
therefore x = 2/√15.