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a compound microscope is made using a lens of focal length 10mm as objective and another lens of focal length 15mm as eye piece .an object is held 1.1cm from objective and final image is obtained at infinite.calculate distance between objective and eye piece. expalin briefly plz.
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a compound microscope is made using a lens of focal length 10mm as obj...
Compound Microscope Calculation

To calculate the distance between objective and eye piece in a compound microscope, we need to use the formula:

1/f = 1/v - 1/u


  • f = focal length

  • v = image distance

  • u = object distance


Given Data:


  • Objective focal length = 10mm

  • Eye piece focal length = 15mm

  • Object distance = 1.1cm = 11mm

  • Final image is obtained at infinite


Solution:

As per the given data, the final image is obtained at infinite. Hence, we can assume that the image distance for the objective lens is equal to the focal length of the eye piece lens.

Therefore, using the formula:

1/f = 1/v - 1/u

For the objective lens:

1/10 = 1/v - 1/11

1/v = 1/10 + 1/11

1/v = 21/110

v = 110/21 = 5.238mm

For the eye piece lens:

1/15 = 1/infinity - 1/5.238

1/infinity = 1/15 + 1/5.238

1/infinity = 0.146

Therefore, the distance between the objective and eye piece is the sum of the focal lengths of the objective and eye piece lenses:

Distance = 10 + 15 = 25mm

Conclusion:

The distance between objective and eye piece in the given compound microscope is 25mm.
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a compound microscope is made using a lens of focal length 10mm as obj...
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A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The object distance for eye-piece, so that final image is formed at the least distance of distinct vision, will be

A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. How far from the objective should an object be placed in order to obtain the condition described in part (i)?

a compound microscope is made using a lens of focal length 10mm as objective and another lens of focal length 15mm as eye piece .an object is held 1.1cm from objective and final image is obtained at infinite.calculate distance between objective and eye piece. expalin briefly plz.
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