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When the width of all classes is same, frequency polygon has not the same area as the Histogram.
  • a)
    True
  • b)
    False
  • c)
    Both
  • d)
    None
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
When the width of all classes is same, frequency polygon has not the s...
Explanation:
Histogram and frequency polygon are graphical representations of frequency distribution. When the width of all classes is the same, the frequency polygon and histogram are similar in shape. However, they differ in one important aspect - the area enclosed by the frequency polygon is not the same as the area enclosed by the histogram.

Here are the reasons why:

- Histograms use bars to represent the frequency of each class interval. The height of each bar corresponds to the frequency of the class interval, and the width of the bar corresponds to the width of the class interval. The area of each bar is equal to the product of its height and width. Therefore, the area of the entire histogram represents the total frequency of the data set.
- Frequency polygons, on the other hand, use line segments to connect the midpoints of each class interval. The height of each point on the frequency polygon corresponds to the frequency density of the class interval, which is the frequency divided by the width of the class interval. The area enclosed by the frequency polygon is the area under the curve formed by the line segments.

Therefore, the area enclosed by the frequency polygon is not equal to the area enclosed by the histogram, even when the width of all classes is the same.

In conclusion, the statement "When the width of all classes is same, frequency polygon has not the same area as the Histogram" is true.
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Community Answer
When the width of all classes is same, frequency polygon has not the s...
False
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When the width of all classes is same, frequency polygon has not the same area as the Histogram.a)Trueb)Falsec)Bothd)NoneCorrect answer is option 'B'. Can you explain this answer?
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