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Uniform wire 16 Ω resistance is made in the form of a square. Two opposite corners of the square are connected by a wire of resistance of 16 Ω . The effective resistance between the other two opposite corners is
  • a)
    32 Ω
  • b)
    16 Ω
  • c)
    8 Ω
  • d)
    4 Ω
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Uniform wire 16 resistance is made in the form of a square. Two oppos...
Given:
- A uniform wire with resistance of 16 ohms is made in the form of a square.
- Two opposite corners of the square are connected by a wire of resistance 16 ohms.

To find:
- The effective resistance between the other two opposite corners.

Solution:
1. Let's assume the length of each side of the square is 'L'.
2. The resistance of a wire is given by the formula:
Resistance (R) = Resistivity (ρ) * Length (L) / Area (A)
Since the wire is uniform, the resistivity and length are constant. Thus, the resistance is inversely proportional to the area.
3. The resistance between two opposite corners of the square is 16 ohms. This resistance is contributed by two sides of the square, each having a resistance of 16 ohms.
4. Let's consider one side of the square. The resistance of this side is given by:
Resistance (R1) = Resistivity (ρ) * Length (L) / Area1
Since R1 = 16 ohms, we have:
16 = ρ * L / Area1 ----(Equation 1)
5. Now, let's consider the other two opposite corners of the square. The resistance between these corners can be found by adding the resistances of two sides of the square.
Resistance (R2) = R1 + R1
= 2 * R1
Since R2 = 16 ohms, we have:
16 = 2 * ρ * L / Area1 ----(Equation 2)
6. Dividing Equation 2 by Equation 1, we get:
16 / 16 = (2 * ρ * L / Area1) / (ρ * L / Area1)
1 = 2
7. The above equation is not possible, so our assumption that the wire is a square is incorrect.
8. However, if we consider a wire that is a rectangle instead of a square, we can find a solution.
9. Let's assume the length of the rectangle is 'L' and the breadth is 'B'.
10. The resistance of one side of the rectangle is given by:
Resistance (R1) = Resistivity (ρ) * Length (L) / Area1
Since R1 = 16 ohms, we have:
16 = ρ * L / Area1 ----(Equation 3)
11. The resistance between the other two opposite corners of the rectangle is given by:
Resistance (R2) = R1 + R1
= 2 * R1
Since R2 = 16 ohms, we have:
16 = 2 * ρ * L / Area1 ----(Equation 4)
12. Dividing Equation 4 by Equation 3, we get:
16 / 16 = (2 * ρ * L / Area1) / (ρ * L / Area1)
1 = 2
13. Again, the above equation is not possible.
14. Therefore, there is no possible shape of the wire (square or rectangle) that satisfies the given conditions.
15. Hence, the effective resistance between the other two opposite corners cannot be determined.

Therefore, the correct
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Uniform wire 16 resistance is made in the form of a square. Two opposite corners of the square are connected by a wire of resistance of 16 . The effective resistance between the other two opposite corners isa)32 b)16 c)8 d)4 Correct answer is option 'D'. Can you explain this answer?
Question Description
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