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The value of the limit when x tends to 2 of the expression (x-2)-1-(x2-3x+2)-1 is
  • a)
    1
  • b)
    0
  • c)
    -1
  • d)
    None
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The value of the limit when x tends to 2 of the expression (x-2)-1-(x2...
The given expression is:
(x-2)-1-(x2-3x 2)-1

Breaking down the expression:
(x-2)-1 can be rewritten as 1/(x-2)
(x2-3x 2)-1 can be rewritten as 1/(x^2-3x+2)

Re-writing the expression:
The given expression can be written as 1/(x-2) - 1/(x^2-3x+2)

Finding the limit:
We are required to find the limit of the expression as x tends to 2.

Approach:
We can find the limit by plugging in the value of x equals to 2 into the expression.

Substituting x = 2:
When we substitute x = 2 in the expression, we get:
1/(2-2) - 1/(2^2-3(2)+2)
= 1/0 - 1/(4-6+2)
= 1/0 - 1/0
Since we have a division by zero in the expression, the limit does not exist.

Conclusion:
The value of the limit when x tends to 2 of the given expression is undefined or does not exist. Therefore, the correct answer is option 'd' (None).
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The value of the limit when x tends to 2 of the expression (x-2)-1-(x2-3x+2)-1isa)1b)0c)-1d)NoneCorrect answer is option 'A'. Can you explain this answer?
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