Answer:

Explanation:

A leap year is a year that is divisible by 4, except for years that are divisible by 100 but not divisible by 400. Therefore, there are 366 days in a leap year.

To find the probability that a leap year selected at random would contain 53 Saturdays, we need to determine the number of leap years that have 53 Saturdays and divide that by the total number of leap years.

Step 1: Determine the number of days in a year that are Saturdays.

There are 52 weeks in a year, which means there are 52 Saturdays. However, in a leap year, there are 2 extra days. Therefore, there can be 52 or 53 Saturdays in a leap year.

Step 2: Determine the number of leap years that have 53 Saturdays.

To determine the number of leap years that have 53 Saturdays, we need to count the number of leap years that have 366 days and start on a Saturday. The first leap year to start on a Saturday is 1752. We can then count the number of leap years that start on a Saturday until we reach the present year. For example, if we were in the year 2021, we would count the number of leap years that start on a Saturday between 1752 and 2020.

Step 3: Determine the total number of leap years.

To determine the total number of leap years, we need to divide the number of years that have passed since 1752 by 4. However, we need to exclude the years that are divisible by 100 but not divisible by 400. For example, the year 1900 was not a leap year because it is divisible by 100 but not divisible by 400.

Step 4: Calculate the probability.

Once we have determined the number of leap years that have 53 Saturdays and the total number of leap years, we can calculate the probability by dividing the number of leap years that have 53 Saturdays by the total number of leap years.

Therefore, the correct answer is option B, 2/7.

A leap year would perfectly be fitted for 52 weeks
hence the other two days can be
1) mon,tue
2)tue,we'd
3) we'd,thurs
4) thurs,Fri
5) Fri,sat
6) Sat,sun
7) sun,mon
in which every day is repeated two times hence probability would be 2/7 for getting 53 Sundays or anydays