In Parallelogram ABCD, bisectors of angles A and B intersect each othe...
In a parallelogram ABCD, the bisectors of angles A and B intersect at point O. The following explanation details the calculation of the measure of ∠AOB.
Parallelogram Properties
In parallelogram ABCD, angles A and B are supplementary, which means:
∠A + ∠B = 180°
Angle Bisectors
The bisectors of angles A and B intersect at O, forming angles:
∠OAB = ½∠A and ∠OBA = ½∠B
Forming ∠AOB
Angle ∠AOB can be calculated as:
∠AOB = 360° - (∠OAB + ∠OBA + ∠AOB'), where ∠AOB' is the angle opposite ∠AOB within triangle AOB.
Sum in Triangle AOB
In triangle AOB, the sum of angles is:
∠OAB + ∠OBA + ∠AOB' = 180°
Using Supplementary Angles
Given that ∠A and ∠B are supplementary:
∠AOB' = 180° - (½∠A + ½∠B) = 180° - ½ × 180° = 90°
Calculating ∠AOB
Since ∠AOB and ∠AOB' form a straight line at point O:
∠AOB = 360° - 180° - 90° = 90°
Therefore, the measure of ∠AOB is 90°.