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Patliputra, capital of Bihar has 10000 families.It was found that 40% families buy newspaper Anand Patrika, 20% families buy newspaper Bharat and 10% families buy newspaper City News , 5% families buy Anand Patrika and Bharat, 3% buy Bharat and City News and 4% buy Anand patrika and City news. If 2% families buy all the three newspapers, then the number of families that buy none of these newspapers is
  • a)
    4000
  • b)
    3300
  • c)
    4200
  • d)
    5000
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Patliputra, capital of Bihar has 10000 families.It was found that 40% ...
Let Anand Patrika be A. Bharat be B . City News be C.
Number of families who buy none of A, B and C = N - n(A ∪ B ∪ C), 
where N = Total number of families.
n(A): Number of Newspaper A readers.
n(B): Number of Newspaper B readers.
n(C): Number of Newspaper C readers. 
Number of families who buy none of A, B and C
= 10000 - {n(A) + n(B) + n(C) - n(A ∩ B) - n(B ∩ C) - n(A ∩ C) + n(A ∩ B ∩ C)}
= 10000 - 4000 - 2000 - 1000 + 500 + 300 + 400 - 200 
= 4000
Number of families who buy none of A, B and C = 4000
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Most Upvoted Answer
Patliputra, capital of Bihar has 10000 families.It was found that 40% ...
Given Information:
- Total number of families in Patliputra, the capital of Bihar = 10,000
- Percentage of families buying each newspaper:
- Anand Patrika = 40%
- Bharat = 20%
- City News = 10%
- Percentage of families buying multiple newspapers:
- Anand Patrika and Bharat = 5%
- Bharat and City News = 3%
- Anand Patrika and City News = 4%
- All three newspapers = 2%

To find the number of families that buy none of these newspapers, we need to subtract the total number of families buying any of these newspapers from the total number of families in Patliputra.

Solution:

Step 1: Calculate the number of families buying each newspaper:
- Number of families buying Anand Patrika = 40% of 10,000 = 4,000
- Number of families buying Bharat = 20% of 10,000 = 2,000
- Number of families buying City News = 10% of 10,000 = 1,000

Step 2: Calculate the number of families buying multiple newspapers:
- Number of families buying Anand Patrika and Bharat = 5% of 10,000 = 500
- Number of families buying Bharat and City News = 3% of 10,000 = 300
- Number of families buying Anand Patrika and City News = 4% of 10,000 = 400
- Number of families buying all three newspapers = 2% of 10,000 = 200

Step 3: Calculate the number of families buying at least one newspaper:
- Number of families buying Anand Patrika or Bharat or City News = (Number of families buying Anand Patrika) + (Number of families buying Bharat) + (Number of families buying City News) - (Number of families buying Anand Patrika and Bharat) - (Number of families buying Bharat and City News) - (Number of families buying Anand Patrika and City News) + (Number of families buying all three newspapers)
= 4,000 + 2,000 + 1,000 - 500 - 300 - 400 + 200
= 6,000

Step 4: Calculate the number of families buying none of these newspapers:
- Number of families buying none of these newspapers = Total number of families - Number of families buying at least one newspaper
= 10,000 - 6,000
= 4,000

Therefore, the number of families that buy none of these newspapers is 4,000.

Hence, the correct answer is option A) 4,000.
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Patliputra, capital of Bihar has 10000 families.It was found that 40% families buy newspaper Anand Patrika, 20% families buy newspaper Bharat and 10% families buy newspaper City News , 5% families buy Anand Patrika and Bharat, 3% buy Bharat and City News and 4% buy Anand patrika and City news. If 2% families buy all the three newspapers, then the number of families that buy none of these newspapers isa)4000b)3300c)4200d)5000Correct answer is option 'A'. Can you explain this answer?
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