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A parallel plate capacitor with plate area of 5 cm2 and plate separation of 3 mm has a voltage 50sin103t applied to its plate. Calculate the displacement current assuming ε = 2ε0.
  • a)
    147.4 cos103tnA
  • b)
    125.8 cos103tμA
  • c)
    166.2 cos103tnA
  • d)
    99 cos103tμA
Correct answer is option 'A'. Can you explain this answer?
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A parallel plate capacitor with plate area of 5 cm2 and plate separati...

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A parallel plate capacitor with plate area of 5 cm2 and plate separati...
To calculate the displacement current, we need to use the formula:

Displacement Current = ε₀ * dΦE/dt

Where:
ε₀ is the permittivity of free space (8.85 x 10^-12 F/m)
dΦE/dt is the rate of change of electric flux through the capacitor plates

To find dΦE/dt, we need to calculate the electric field between the plates of the capacitor. The electric field can be calculated using the formula:

E = V/d

Where:
E is the electric field
V is the voltage applied
d is the plate separation

Given:
Plate area (A) = 5 cm² = 5 x 10^-4 m²
Plate separation (d) = 3 mm = 3 x 10^-3 m
Voltage (V) = 50sin(103t)

First, let's calculate the electric field:

E = V/d
E = (50sin(103t))/(3 x 10^-3)

Next, let's calculate the rate of change of electric flux:

dΦE/dt = E * A
dΦE/dt = (50sin(103t))/(3 x 10^-3) * 5 x 10^-4

Finally, let's calculate the displacement current:

Displacement Current = ε₀ * dΦE/dt
Displacement Current = 8.85 x 10^-12 * (50sin(103t))/(3 x 10^-3) * 5 x 10^-4

Simplifying the expression:

Displacement Current = (0.148sin(103t))/(3 x 10^-3)
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A parallel plate capacitor with plate area of 5 cm2 and plate separation of 3 mm has a voltage 50sin103tapplied to its plate. Calculate the displacement current assuming ε = 2ε0.a)147.4 cos103tnAb)125.8 cos103tμAc)166.2 cos103tnAd)99 cos103tμACorrect answer is option 'A'. Can you explain this answer?
Question Description
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