The following two cells with initial concentration as given are connected with each other.(1) Fe(s) - Fe(NO3)2(aq.) (1M) -- SnCl2(aq.) (1M) - Sn(s)(2) Zn(s) - ZnSO4(aq.) (1M) -- Fe(NO3)2(aq.) (1M) - Fe(s)After sufficient time equilibrium is established in the circuit. What will be the concentrations (in mmoles/L) of Fe2+ ions in first and second cells respectively ?(use only 3 significant figures to fill your answer. For example if [Fe2+]1 = 0.225M and [Fe2+]2 = 0.425M then your answer should be 225425)= -0.44 V, 2.3 x RT = 6433, log2 = 0.3]Correct answer is '667'. Can you explain this answer?

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The following two cells with initial concentration as given are connected with each other.
(1) Fe(s) | Fe(NO₃)₂(aq.) (1M) || SnCl₂(aq.) (1M) | Sn(s)
(2) Zn(s) | ZnSO₄(aq.) (1M) || Fe(NO₃)₂(aq.) (1M) | Fe(s)
After sufficient time equilibrium is established in the circuit. What will be the concentrations (in mmoles/L) of Fe²⁺ ions in first and second cells respectively ?
(use only 3 significant figures to fill your answer. For example if [Fe²⁺]₁ = 0.225M and [Fe²⁺]₂ = 0.425M then your answer should be 225425)

= -0.44 V, 2.3 x RT = 6433, log2 = 0.3]

Correct answer is '667'. Can you explain this answer?

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The following two cells with initial concentration as given are connec...

If above cells are connected in parallel then first cell will get charged up and second cell will get discharged so net cell reaction will be.

Fe₂²⁺(aq.) + Fe₁²⁺ (aq.)

Zn²⁺ (aq.) + Sn²⁺(aq.) E°_net = 0.02

So, - 2.30 RT log k_eq = -2 x 96500 x 0.02

⇒ x = 1/3
So, concentration of Fe²⁺ ions in the first cell

= concentration of Fe²⁺ ions in the second cell = 2/3 M = 667 mmoles/L.

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The following two cells with initial concentration as given are connected with each other.(1) Fe(s) | Fe(NO3)2(aq.) (1M) || SnCl2(aq.) (1M) | Sn(s)(2) Zn(s) | ZnSO4(aq.) (1M) || Fe(NO3)2(aq.) (1M) | Fe(s)After sufficient time equilibrium is established in the circuit. What will be the concentrations (in mmoles/L) of Fe2+ ions in first and second cells respectively ?(use only 3 significant figures to fill your answer. For example if [Fe2+]1 = 0.225M and [Fe2+]2 = 0.425M then your answer should be 225425)= -0.44 V, 2.3 x RT = 6433, log2 = 0.3]Correct answer is '667'. Can you explain this answer?

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The following two cells with initial concentration as given are connected with each other.(1) Fe(s) | Fe(NO3)2(aq.) (1M) || SnCl2(aq.) (1M) | Sn(s)(2) Zn(s) | ZnSO4(aq.) (1M) || Fe(NO3)2(aq.) (1M) | Fe(s)After sufficient time equilibrium is established in the circuit. What will be the concentrations (in mmoles/L) of Fe2+ ions in first and second cells respectively ?(use only 3 significant figures to fill your answer. For example if [Fe2+]1 = 0.225M and [Fe2+]2 = 0.425M then your answer should be 225425)= -0.44 V, 2.3 x RT = 6433, log2 = 0.3]Correct answer is '667'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The following two cells with initial concentration as given are connected with each other.(1) Fe(s) | Fe(NO3)2(aq.) (1M) || SnCl2(aq.) (1M) | Sn(s)(2) Zn(s) | ZnSO4(aq.) (1M) || Fe(NO3)2(aq.) (1M) | Fe(s)After sufficient time equilibrium is established in the circuit. What will be the concentrations (in mmoles/L) of Fe2+ ions in first and second cells respectively ?(use only 3 significant figures to fill your answer. For example if [Fe2+]1 = 0.225M and [Fe2+]2 = 0.425M then your answer should be 225425)= -0.44 V, 2.3 x RT = 6433, log2 = 0.3]Correct answer is '667'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The following two cells with initial concentration as given are connected with each other.(1) Fe(s) | Fe(NO3)2(aq.) (1M) || SnCl2(aq.) (1M) | Sn(s)(2) Zn(s) | ZnSO4(aq.) (1M) || Fe(NO3)2(aq.) (1M) | Fe(s)After sufficient time equilibrium is established in the circuit. What will be the concentrations (in mmoles/L) of Fe2+ ions in first and second cells respectively ?(use only 3 significant figures to fill your answer. For example if [Fe2+]1 = 0.225M and [Fe2+]2 = 0.425M then your answer should be 225425)= -0.44 V, 2.3 x RT = 6433, log2 = 0.3]Correct answer is '667'. Can you explain this answer?.

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