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The width of each of ten classes in a frequency distribution is 2.5 and the lower class boundary of the lowest class is 10.6. Which one of the following is the upper class boundary of the highest class?
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The width of each of ten classes in a frequency distribution is 2.5 an...
Calculating Upper Class Boundary

To calculate the upper class boundary of the highest class in a frequency distribution, we need to use the following formula:

Upper Class Boundary = Lower Class Boundary + Class Width

The given information in the question is as follows:

- Width of each class = 2.5
- Lower class boundary of the lowest class = 10.6

Calculating Upper Class Boundary of the Highest Class:

To calculate the upper class boundary of the highest class, we need to follow the given steps:

1. Determine the upper limit of the lowest class:

The upper limit of the lowest class is calculated by subtracting 0.5 from the lower class boundary of the second class.

Upper Limit of the Lowest Class = Lower Class Boundary of Second Class - 0.5

As we know the width of each class is 2.5, the lower class boundary of the second class can be calculated by adding 2.5 to the lower class boundary of the first class.

Lower Class Boundary of Second Class = Lower Class Boundary of First Class + Class Width

= 10.6 + 2.5

= 13.1

Therefore, the upper limit of the lowest class is:

Upper Limit of the Lowest Class = 13.1 - 0.5 = 12.6

2. Determine the upper class boundary of the highest class:

The upper class boundary of the highest class is calculated by adding 0.5 to the upper limit of the highest class.

Upper Class Boundary of Highest Class = Upper Limit of Highest Class + 0.5

As we know the width of each class is 2.5, the upper limit of the highest class can be calculated by adding 2.5 to the upper limit of the second last class.

Upper Limit of the Second Last Class = Upper Limit of the Highest Class - Class Width

= Upper Limit of the Highest Class - 2.5

Therefore, the upper class boundary of the highest class is:

Upper Class Boundary of Highest Class = Upper Limit of Second Last Class + 0.5

= (Upper Limit of Highest Class - 2.5) + 0.5

= Upper Limit of Highest Class - 2 + 0.5

= Upper Limit of Highest Class - 1.5

We know that the width of each class is 2.5, so the upper limit of the highest class can be calculated by subtracting 2.5 from the upper class boundary of the highest class.

Upper Limit of Highest Class = Upper Class Boundary of Highest Class - Class Width

= Upper Class Boundary of Highest Class - 2.5

Therefore, the upper class boundary of the highest class is:

Upper Class Boundary of Highest Class = Upper Limit of Highest Class + 0.5

= (Upper Class Boundary of Highest Class - 2.5) + 0.5

= Upper Class Boundary of Highest Class - 2

= 10.6 + 2.5 x 10 - 2

= 33.1

Therefore, the upper class boundary of the highest class is 33.1.
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The width of each of ten classes in a frequency distribution is 2.5 and the lower class boundary of the lowest class is 10.6. Which one of the following is the upper class boundary of the highest class?
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The width of each of ten classes in a frequency distribution is 2.5 and the lower class boundary of the lowest class is 10.6. Which one of the following is the upper class boundary of the highest class? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about The width of each of ten classes in a frequency distribution is 2.5 and the lower class boundary of the lowest class is 10.6. Which one of the following is the upper class boundary of the highest class? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The width of each of ten classes in a frequency distribution is 2.5 and the lower class boundary of the lowest class is 10.6. Which one of the following is the upper class boundary of the highest class?.
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