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(a) Consider an infinite geometric series with first term a and common ratio r. If the sum is 4 and the second term is 3/4, then [JEE 2000, (scr.), 1 + 1](A) a =, r =(B) a = 2, r =(C) a = , r =(D) a = 3, r =(b) If a, b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisifes the relation :(A) 0 £ M £ 1 (B) 1 £ M £ 2 (C) 2 £ M £ 3 (D) 3 £ M £ 4(c) The fourth power of the common difference of an arithmetic progression with integer entries added to the product of any four consecutive terms of it. Prove that the resulting sum is the square of an integer. [JEE 2000, (Mains), 4]Correct answer is '(a) D (b) A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about (a) Consider an infinite geometric series with first term a and common ratio r. If the sum is 4 and the second term is 3/4, then [JEE 2000, (scr.), 1 + 1](A) a =, r =(B) a = 2, r =(C) a = , r =(D) a = 3, r =(b) If a, b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisifes the relation :(A) 0 £ M £ 1 (B) 1 £ M £ 2 (C) 2 £ M £ 3 (D) 3 £ M £ 4(c) The fourth power of the common difference of an arithmetic progression with integer entries added to the product of any four consecutive terms of it. Prove that the resulting sum is the square of an integer. [JEE 2000, (Mains), 4]Correct answer is '(a) D (b) A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for (a) Consider an infinite geometric series with first term a and common ratio r. If the sum is 4 and the second term is 3/4, then [JEE 2000, (scr.), 1 + 1](A) a =, r =(B) a = 2, r =(C) a = , r =(D) a = 3, r =(b) If a, b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisifes the relation :(A) 0 £ M £ 1 (B) 1 £ M £ 2 (C) 2 £ M £ 3 (D) 3 £ M £ 4(c) The fourth power of the common difference of an arithmetic progression with integer entries added to the product of any four consecutive terms of it. Prove that the resulting sum is the square of an integer. [JEE 2000, (Mains), 4]Correct answer is '(a) D (b) A'. Can you explain this answer?.

Solutions for (a) Consider an infinite geometric series with first term a and common ratio r. If the sum is 4 and the second term is 3/4, then [JEE 2000, (scr.), 1 + 1](A) a =, r =(B) a = 2, r =(C) a = , r =(D) a = 3, r =(b) If a, b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisifes the relation :(A) 0 £ M £ 1 (B) 1 £ M £ 2 (C) 2 £ M £ 3 (D) 3 £ M £ 4(c) The fourth power of the common difference of an arithmetic progression with integer entries added to the product of any four consecutive terms of it. Prove that the resulting sum is the square of an integer. [JEE 2000, (Mains), 4]Correct answer is '(a) D (b) A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of (a) Consider an infinite geometric series with first term a and common ratio r. If the sum is 4 and the second term is 3/4, then [JEE 2000, (scr.), 1 + 1](A) a =, r =(B) a = 2, r =(C) a = , r =(D) a = 3, r =(b) If a, b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisifes the relation :(A) 0 £ M £ 1 (B) 1 £ M £ 2 (C) 2 £ M £ 3 (D) 3 £ M £ 4(c) The fourth power of the common difference of an arithmetic progression with integer entries added to the product of any four consecutive terms of it. Prove that the resulting sum is the square of an integer. [JEE 2000, (Mains), 4]Correct answer is '(a) D (b) A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of (a) Consider an infinite geometric series with first term a and common ratio r. If the sum is 4 and the second term is 3/4, then [JEE 2000, (scr.), 1 + 1](A) a =, r =(B) a = 2, r =(C) a = , r =(D) a = 3, r =(b) If a, b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisifes the relation :(A) 0 £ M £ 1 (B) 1 £ M £ 2 (C) 2 £ M £ 3 (D) 3 £ M £ 4(c) The fourth power of the common difference of an arithmetic progression with integer entries added to the product of any four consecutive terms of it. Prove that the resulting sum is the square of an integer. [JEE 2000, (Mains), 4]Correct answer is '(a) D (b) A'. Can you explain this answer?, a detailed solution for (a) Consider an infinite geometric series with first term a and common ratio r. If the sum is 4 and the second term is 3/4, then [JEE 2000, (scr.), 1 + 1](A) a =, r =(B) a = 2, r =(C) a = , r =(D) a = 3, r =(b) If a, b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisifes the relation :(A) 0 £ M £ 1 (B) 1 £ M £ 2 (C) 2 £ M £ 3 (D) 3 £ M £ 4(c) The fourth power of the common difference of an arithmetic progression with integer entries added to the product of any four consecutive terms of it. Prove that the resulting sum is the square of an integer. [JEE 2000, (Mains), 4]Correct answer is '(a) D (b) A'. Can you explain this answer? has been provided alongside types of (a) Consider an infinite geometric series with first term a and common ratio r. If the sum is 4 and the second term is 3/4, then [JEE 2000, (scr.), 1 + 1](A) a =, r =(B) a = 2, r =(C) a = , r =(D) a = 3, r =(b) If a, b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisifes the relation :(A) 0 £ M £ 1 (B) 1 £ M £ 2 (C) 2 £ M £ 3 (D) 3 £ M £ 4(c) The fourth power of the common difference of an arithmetic progression with integer entries added to the product of any four consecutive terms of it. Prove that the resulting sum is the square of an integer. [JEE 2000, (Mains), 4]Correct answer is '(a) D (b) A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice (a) Consider an infinite geometric series with first term a and common ratio r. If the sum is 4 and the second term is 3/4, then [JEE 2000, (scr.), 1 + 1](A) a =, r =(B) a = 2, r =(C) a = , r =(D) a = 3, r =(b) If a, b, c, d are positive real numbers such that a + b + c + d = 2, then M = (a + b) (c + d) satisifes the relation :(A) 0 £ M £ 1 (B) 1 £ M £ 2 (C) 2 £ M £ 3 (D) 3 £ M £ 4(c) The fourth power of the common difference of an arithmetic progression with integer entries added to the product of any four consecutive terms of it. Prove that the resulting sum is the square of an integer. [JEE 2000, (Mains), 4]Correct answer is '(a) D (b) A'. Can you explain this answer? tests, examples and also practice JEE tests.