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For a saturated solution of AgCl at 25ºC, k=3.4 x 10-6cm-1and that of H2O(l) used is 2.02 x 10-6ohm-1cm-1.for AgCl is 138 ohm-1mol-1,then the solubility of AgCl in moles per liter will be:a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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For a saturated solution of AgCl at 25ºC, k=3.4 x 10-6cm-1and that of H2O(l) used is 2.02 x 10-6ohm-1cm-1.for AgCl is 138 ohm-1mol-1,then the solubility of AgCl in moles per liter will be:a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer?, a detailed solution for For a saturated solution of AgCl at 25ºC, k=3.4 x 10-6cm-1and that of H2O(l) used is 2.02 x 10-6ohm-1cm-1.for AgCl is 138 ohm-1mol-1,then the solubility of AgCl in moles per liter will be:a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of For a saturated solution of AgCl at 25ºC, k=3.4 x 10-6cm-1and that of H2O(l) used is 2.02 x 10-6ohm-1cm-1.for AgCl is 138 ohm-1mol-1,then the solubility of AgCl in moles per liter will be:a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice For a saturated solution of AgCl at 25ºC, k=3.4 x 10-6cm-1and that of H2O(l) used is 2.02 x 10-6ohm-1cm-1.for AgCl is 138 ohm-1mol-1,then the solubility of AgCl in moles per liter will be:a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.