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For a saturated solution of AgCl at 25ºC, k=3.4 x 10-6 cm-1 and that of H2O(l) used is 2.02 x 10-6 ohm-1 cm-1. for AgCl is 138 ohm-1mol-1,then the solubility of AgCl in moles per liter will be:
  • a)
    10–5
  • b)
    10–10
  • c)
    10–14
  • d)
    10–16
Correct answer is option 'A'. Can you explain this answer?
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For a saturated solution of AgCl at 25ºC, k=3.4 x 10-6cm-1and tha...
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For a saturated solution of AgCl at 25ºC, k=3.4 x 10-6cm-1and that of H2O(l) used is 2.02 x 10-6ohm-1cm-1.for AgCl is 138 ohm-1mol-1,then the solubility of AgCl in moles per liter will be:a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer?
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For a saturated solution of AgCl at 25ºC, k=3.4 x 10-6cm-1and that of H2O(l) used is 2.02 x 10-6ohm-1cm-1.for AgCl is 138 ohm-1mol-1,then the solubility of AgCl in moles per liter will be:a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about For a saturated solution of AgCl at 25ºC, k=3.4 x 10-6cm-1and that of H2O(l) used is 2.02 x 10-6ohm-1cm-1.for AgCl is 138 ohm-1mol-1,then the solubility of AgCl in moles per liter will be:a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a saturated solution of AgCl at 25ºC, k=3.4 x 10-6cm-1and that of H2O(l) used is 2.02 x 10-6ohm-1cm-1.for AgCl is 138 ohm-1mol-1,then the solubility of AgCl in moles per liter will be:a)10–5b)10–10c)10–14d)10–16Correct answer is option 'A'. Can you explain this answer?.
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