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The differential coefficients of (x2 +1)/x is
- a)1 + 1/x2
- b)1 – 1/x2
- c)1/x2
- d)none of these
Correct answer is option 'B'. Can you explain this answer?
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The differential coefficients of (x2 +1)/x isa)1 + 1/x2b)1 1/x2c)1/x2...
Solution:
We have to find the differential coefficients of (x2 + 1)/x.
To find the differential coefficient, we have to differentiate the given function with respect to x.
Let y = (x2 + 1)/x
Taking the derivative of both sides with respect to x, we get
dy/dx = d/dx [(x2 + 1)/x]
Using the quotient rule of differentiation, we get
dy/dx = [(x2 + 1)d/dx(x) - x d/dx(x2 + 1)]/x2
Simplifying the above expression, we get
dy/dx = [(x2 + 1) - x(2x)]/x2
dy/dx = (1 - x2)/x2
Therefore, the differential coefficient of (x2 + 1)/x is (1 - x2)/x2.
Answer: Option B (1 - x2)/x2.
We have to find the differential coefficients of (x2 + 1)/x.
To find the differential coefficient, we have to differentiate the given function with respect to x.
Let y = (x2 + 1)/x
Taking the derivative of both sides with respect to x, we get
dy/dx = d/dx [(x2 + 1)/x]
Using the quotient rule of differentiation, we get
dy/dx = [(x2 + 1)d/dx(x) - x d/dx(x2 + 1)]/x2
Simplifying the above expression, we get
dy/dx = [(x2 + 1) - x(2x)]/x2
dy/dx = (1 - x2)/x2
Therefore, the differential coefficient of (x2 + 1)/x is (1 - x2)/x2.
Answer: Option B (1 - x2)/x2.
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Community Answer
The differential coefficients of (x2 +1)/x isa)1 + 1/x2b)1 1/x2c)1/x2...
(x²+1)/x = x²/x + 1/x = x + 1/x
Differential = 1 - 1/x²
Formula is differential of x^n = n x^n-1
Differential = 1 - 1/x²
Formula is differential of x^n = n x^n-1
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