Passage for Q. N os. (8-9)The concentration of potassium ions inside a biological cell is at least twenty times higher than the outside. The resulting potential difference across the cell is important in several processes such as transmission of nerve impulses and maintaining the ion balance. A simple model for such a concentration cell involving a metal M is M(s) - M+ (aq 0.05 molar) -- M+ (ag; 1 molar) - M(s).For the above electrolytic cell the magnitude of the cell potential - Ecell- = 70 mV.Q.For the above cella)Ecell andlt; 0 , andDelta;Ganddeg; andgt; 0b)Ecellandgt; 0 , andDelta;Ganddeg; andlt;0c)Ecellandgt;0 , andDelta;Ganddeg;andgt;0d)None of theseCorrect answer is option 'B'. Can you explain this answer?

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Passage for Q. N os. (8-9)

The concentration of potassium ions inside a biological cell is at least twenty times higher than the outside. The resulting potential difference across the cell is important in several processes such as transmission of nerve impulses and maintaining the ion balance. A simple model for such a concentration cell involving a metal M is M(s) | M⁺ (aq 0.05 molar) | | M⁺ (ag; 1 molar) | M(s).
For the above electrolytic cell the magnitude of the cell potential | E_cell | = 70 mV.

For the above cell

a)
E_cell < 0 , ΔG^° > 0
b)
E_cell > 0 , ΔG^° < 0
c)
E_cell > 0 , ΔG^° >0
d)
None of these

Correct answer is option 'B'. Can you explain this answer?

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Explanation:

Cell Potential and Gibbs Free Energy:
- The cell potential (Ecell) is a measure of the driving force or the spontaneity of a redox reaction.
- A positive cell potential indicates a spontaneous reaction, while a negative cell potential indicates a non-spontaneous reaction.
- The Gibbs free energy change (ΔG°) of a reaction is related to the cell potential by the equation ΔG° = -nFE°, where n is the number of electrons transferred and F is the Faraday constant.

Relation between Ecell and ΔG°:
- If Ecell is positive, then the reaction is spontaneous (Ecell > 0), and the Gibbs free energy change is negative (ΔG° < />
- If Ecell is negative, then the reaction is non-spontaneous (Ecell < 0),="" and="" the="" gibbs="" free="" energy="" change="" is="" positive="" (δg°="" /> 0).

Applying the Concept to the Given Cell:
- In the given cell, the magnitude of the cell potential |Ecell| = 70 mV, which is positive.
- Since Ecell is positive, the reaction is spontaneous, and the Gibbs free energy change (ΔG°) will be negative.
- Therefore, the correct option is "Ecell > 0, ΔG° < 0"="" (option="" />

Conclusion:
- The relationship between cell potential and Gibbs free energy helps us determine the spontaneity of a redox reaction. In this case, the positive cell potential indicates a spontaneous reaction with a negative Gibbs free energy change.

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Passage for Q. N os. (8-9)The concentration of potassium ions inside a biological cell is at least twenty times higher than the outside. The resulting potential difference across the cell is important in several processes such as transmission of nerve impulses and maintaining the ion balance. A simple model for such a concentration cell involving a metal M is M(s) | M+ (aq 0.05 molar) || M+ (ag; 1 molar) | M(s).For the above electrolytic cell the magnitude of the cell potential | Ecell| = 70 mV.Q.For the above cella)Ecell < 0 , ΔG° > 0b)Ecell> 0 , ΔG° <0c)Ecell>0 , ΔG°>0d)None of theseCorrect answer is option 'B'. Can you explain this answer?

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Passage for Q. N os. (8-9)The concentration of potassium ions inside a biological cell is at least twenty times higher than the outside. The resulting potential difference across the cell is important in several processes such as transmission of nerve impulses and maintaining the ion balance. A simple model for such a concentration cell involving a metal M is M(s) | M+ (aq 0.05 molar) || M+ (ag; 1 molar) | M(s).For the above electrolytic cell the magnitude of the cell potential | Ecell| = 70 mV.Q.For the above cella)Ecell < 0 , ΔG° > 0b)Ecell> 0 , ΔG° <0c)Ecell>0 , ΔG°>0d)None of theseCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Passage for Q. N os. (8-9)The concentration of potassium ions inside a biological cell is at least twenty times higher than the outside. The resulting potential difference across the cell is important in several processes such as transmission of nerve impulses and maintaining the ion balance. A simple model for such a concentration cell involving a metal M is M(s) | M+ (aq 0.05 molar) || M+ (ag; 1 molar) | M(s).For the above electrolytic cell the magnitude of the cell potential | Ecell| = 70 mV.Q.For the above cella)Ecell < 0 , ΔG° > 0b)Ecell> 0 , ΔG° <0c)Ecell>0 , ΔG°>0d)None of theseCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Passage for Q. N os. (8-9)The concentration of potassium ions inside a biological cell is at least twenty times higher than the outside. The resulting potential difference across the cell is important in several processes such as transmission of nerve impulses and maintaining the ion balance. A simple model for such a concentration cell involving a metal M is M(s) | M+ (aq 0.05 molar) || M+ (ag; 1 molar) | M(s).For the above electrolytic cell the magnitude of the cell potential | Ecell| = 70 mV.Q.For the above cella)Ecell < 0 , ΔG° > 0b)Ecell> 0 , ΔG° <0c)Ecell>0 , ΔG°>0d)None of theseCorrect answer is option 'B'. Can you explain this answer?.

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