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A 50Hz, bar primary CT has a secondary with 500turns. The secondary supplies 5A current into a purely resistive burden of 1 ohm. The magnetizing ampere turns is 200. The phase angle between the primary and secondary current is?
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A 50Hz, bar primary CT has a secondary with 500turns. The secondary su...
Primary and Secondary Current Calculation
Using the formula,
Secondary Current (I2) = Primary Current (I1) x (Number of Secondary Turns/Number of Primary Turns)
Substituting the given values, we get:
I2 = I1 x (500/1)
Therefore, I1 = I2/500
Substituting the given values, we get:
I1 = 5/500 = 0.01A
Power Calculation
Using the formula,
Power = Current x Voltage x Power Factor
Since the burden is purely resistive, Power Factor (PF) = 1
Substituting the given values, we get:
Power = 5 x 1 x 1 = 5W
Phase Angle Calculation
Using the formula,
tan(θ) = (Secondary Impedance/Primary Impedance)
Primary Impedance (Z1) = Primary Current (I1) / Magnetizing Ampere Turns (N)
Substituting the given values, we get:
Z1 = 0.01 / 200 = 0.00005 ohm
Secondary Impedance (Z2) = Burden Resistance (R)
Substituting the given value, we get:
Z2 = 1 ohm
Substituting the calculated values in the formula, we get:
tan(θ) = (1/0.00005) = 20,000
Therefore, θ = tan-1(20,000) ≈ 89.9°
Conclusion
The phase angle between primary and secondary current is approximately 89.9°.
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A 50Hz, bar primary CT has a secondary with 500turns. The secondary supplies 5A current into a purely resistive burden of 1 ohm. The magnetizing ampere turns is 200. The phase angle between the primary and secondary current is?
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A 50Hz, bar primary CT has a secondary with 500turns. The secondary supplies 5A current into a purely resistive burden of 1 ohm. The magnetizing ampere turns is 200. The phase angle between the primary and secondary current is? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 50Hz, bar primary CT has a secondary with 500turns. The secondary supplies 5A current into a purely resistive burden of 1 ohm. The magnetizing ampere turns is 200. The phase angle between the primary and secondary current is? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50Hz, bar primary CT has a secondary with 500turns. The secondary supplies 5A current into a purely resistive burden of 1 ohm. The magnetizing ampere turns is 200. The phase angle between the primary and secondary current is?.
A 50Hz, bar primary CT has a secondary with 500turns. The secondary supplies 5A current into a purely resistive burden of 1 ohm. The magnetizing ampere turns is 200. The phase angle between the primary and secondary current is? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 50Hz, bar primary CT has a secondary with 500turns. The secondary supplies 5A current into a purely resistive burden of 1 ohm. The magnetizing ampere turns is 200. The phase angle between the primary and secondary current is? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50Hz, bar primary CT has a secondary with 500turns. The secondary supplies 5A current into a purely resistive burden of 1 ohm. The magnetizing ampere turns is 200. The phase angle between the primary and secondary current is?.
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