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Consider a machine with 64 MB physical memory and a 32-bit virtual address space. If the page size is 4KB, what is the approximate size of the page table?
  • a)
    16 MB
  • b)
    8 MB
  • c)
    2 MB
  • d)
    24 MB
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Consider a machine with 64 MB physical memory and a 32-bit virtual add...
Solution:

Given, physical memory = 64 MB
Virtual address space = 32-bit
Page size = 4 KB

To calculate the page table size, we need to find the number of page table entries.

Number of page table entries = Virtual address space/Page size
= 2^32/2^12
= 2^20

Each page table entry requires 4 bytes (32 bits) for the page frame number.

Therefore, the size of the page table = Number of page table entries x size of each entry
= 2^20 x 4 bytes
= 4 MB

However, this is the size of the page table assuming that each entry takes 4 bytes. In reality, each entry may require additional bits for flags, protection bits, etc. Hence, the actual size of the page table may be slightly larger than 4 MB.

Therefore, the approximate size of the page table is 2 MB (option C).
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Community Answer
Consider a machine with 64 MB physical memory and a 32-bit virtual add...
2MB
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