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Sodium ethoxide has reacted with ethanoyl chloride. The compound that is produced in the a bove reaction is
(AIEEE 2011)
- a)diethyl ether
- b)2-butanone
- c)ethyl chloride
- d)ethyl ethanoate
Correct answer is option 'D'. Can you explain this answer?
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Sodium ethoxide has reacted with ethanoyl chloride. The compound that ...
This is by SN reaction. Cl- is a better leaving group than C2H5O- and then ethyl ethanoate is formed.
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Sodium ethoxide has reacted with ethanoyl chloride. The compound that ...
The reaction between sodium ethoxide (NaOEt) and ethanoyl chloride (CH3COCl) results in the formation of ethyl ethanoate (CH3COOCH2CH3).
Sodium ethoxide is the sodium salt of ethanol (CH3CH2OH) and can be represented as NaOEt. It is a strong base and is commonly used in organic synthesis reactions.
Ethanoyl chloride, also known as acetyl chloride, is an acyl chloride. It is a reactive compound that is often used as a reagent in organic synthesis reactions.
The reaction between sodium ethoxide and ethanoyl chloride is an example of an acyl substitution reaction. In this reaction, the ethanoyl chloride is attacked by the ethoxide ion, resulting in the formation of a new compound.
The key steps involved in the reaction are as follows:
1. Formation of the acyl-oxygen bond: The ethoxide ion (EtO-) attacks the electrophilic carbon of the ethanoyl chloride, resulting in the formation of a tetrahedral intermediate.
2. Elimination of chloride ion: The tetrahedral intermediate is unstable and undergoes elimination of the chloride ion, leading to the formation of an acyloxonium ion.
3. Formation of the ester: The acyloxonium ion is then attacked by another ethoxide ion, resulting in the formation of the ester product, ethyl ethanoate.
The overall reaction can be represented as follows:
CH3COCl + NaOEt → CH3COOCH2CH3 + NaCl
Therefore, the compound produced in the given reaction is ethyl ethanoate (CH3COOCH2CH3), which is also known as ethyl acetate.
Sodium ethoxide is the sodium salt of ethanol (CH3CH2OH) and can be represented as NaOEt. It is a strong base and is commonly used in organic synthesis reactions.
Ethanoyl chloride, also known as acetyl chloride, is an acyl chloride. It is a reactive compound that is often used as a reagent in organic synthesis reactions.
The reaction between sodium ethoxide and ethanoyl chloride is an example of an acyl substitution reaction. In this reaction, the ethanoyl chloride is attacked by the ethoxide ion, resulting in the formation of a new compound.
The key steps involved in the reaction are as follows:
1. Formation of the acyl-oxygen bond: The ethoxide ion (EtO-) attacks the electrophilic carbon of the ethanoyl chloride, resulting in the formation of a tetrahedral intermediate.
2. Elimination of chloride ion: The tetrahedral intermediate is unstable and undergoes elimination of the chloride ion, leading to the formation of an acyloxonium ion.
3. Formation of the ester: The acyloxonium ion is then attacked by another ethoxide ion, resulting in the formation of the ester product, ethyl ethanoate.
The overall reaction can be represented as follows:
CH3COCl + NaOEt → CH3COOCH2CH3 + NaCl
Therefore, the compound produced in the given reaction is ethyl ethanoate (CH3COOCH2CH3), which is also known as ethyl acetate.
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Sodium ethoxide has reacted with ethanoyl chloride. The compound that is produced in the a bove reaction is(AIEEE2011)a)diethyl etherb)2-butanonec)ethyl chlorided)ethyl ethanoateCorrect answer is option 'D'. Can you explain this answer?
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Sodium ethoxide has reacted with ethanoyl chloride. The compound that is produced in the a bove reaction is(AIEEE2011)a)diethyl etherb)2-butanonec)ethyl chlorided)ethyl ethanoateCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Sodium ethoxide has reacted with ethanoyl chloride. The compound that is produced in the a bove reaction is(AIEEE2011)a)diethyl etherb)2-butanonec)ethyl chlorided)ethyl ethanoateCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Sodium ethoxide has reacted with ethanoyl chloride. The compound that is produced in the a bove reaction is(AIEEE2011)a)diethyl etherb)2-butanonec)ethyl chlorided)ethyl ethanoateCorrect answer is option 'D'. Can you explain this answer?.
Sodium ethoxide has reacted with ethanoyl chloride. The compound that is produced in the a bove reaction is(AIEEE2011)a)diethyl etherb)2-butanonec)ethyl chlorided)ethyl ethanoateCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Sodium ethoxide has reacted with ethanoyl chloride. The compound that is produced in the a bove reaction is(AIEEE2011)a)diethyl etherb)2-butanonec)ethyl chlorided)ethyl ethanoateCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Sodium ethoxide has reacted with ethanoyl chloride. The compound that is produced in the a bove reaction is(AIEEE2011)a)diethyl etherb)2-butanonec)ethyl chlorided)ethyl ethanoateCorrect answer is option 'D'. Can you explain this answer?.
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