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If V= 1/2mw^2(x^2 4y^2) for simple harmonic oscillator then find the corresponding Eigen value?
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If V= 1/2mw^2(x^2 4y^2) for simple harmonic oscillator then find the ...
Explanation:
Given Potential Energy Function:
V = 1/2mw^2(x^2 + 4y^2)
Corresponding Eigenvalue:
To find the corresponding eigenvalue, we need to solve the Schrödinger equation for the simple harmonic oscillator using the given potential energy function. The Schrödinger equation for the simple harmonic oscillator is given by:
HΨ = EΨ
Where H is the Hamiltonian operator, Ψ is the wave function, E is the energy eigenvalue, and the Hamiltonian operator for the simple harmonic oscillator is:
H = -ħ^2/2m (∂^2/∂x^2 + ∂^2/∂y^2) + 1/2mw^2(x^2 + 4y^2)
Solving the Schrödinger equation will give us the corresponding eigenvalues for the simple harmonic oscillator.
In this case, the potential energy function is given as V = 1/2mw^2(x^2 + 4y^2), which can be used to determine the Hamiltonian operator and subsequently solve the Schrödinger equation to find the corresponding eigenvalues.
By solving the Schrödinger equation with the given potential energy function, we can determine the eigenvalues associated with the simple harmonic oscillator system.
Therefore, the corresponding eigenvalues can be obtained by solving the Schrödinger equation with the given potential energy function.
Given Potential Energy Function:
V = 1/2mw^2(x^2 + 4y^2)
Corresponding Eigenvalue:
To find the corresponding eigenvalue, we need to solve the Schrödinger equation for the simple harmonic oscillator using the given potential energy function. The Schrödinger equation for the simple harmonic oscillator is given by:
HΨ = EΨ
Where H is the Hamiltonian operator, Ψ is the wave function, E is the energy eigenvalue, and the Hamiltonian operator for the simple harmonic oscillator is:
H = -ħ^2/2m (∂^2/∂x^2 + ∂^2/∂y^2) + 1/2mw^2(x^2 + 4y^2)
Solving the Schrödinger equation will give us the corresponding eigenvalues for the simple harmonic oscillator.
In this case, the potential energy function is given as V = 1/2mw^2(x^2 + 4y^2), which can be used to determine the Hamiltonian operator and subsequently solve the Schrödinger equation to find the corresponding eigenvalues.
By solving the Schrödinger equation with the given potential energy function, we can determine the eigenvalues associated with the simple harmonic oscillator system.
Therefore, the corresponding eigenvalues can be obtained by solving the Schrödinger equation with the given potential energy function.
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If V= 1/2mw^2(x^2 4y^2) for simple harmonic oscillator then find the corresponding Eigen value?
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If V= 1/2mw^2(x^2 4y^2) for simple harmonic oscillator then find the corresponding Eigen value? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about If V= 1/2mw^2(x^2 4y^2) for simple harmonic oscillator then find the corresponding Eigen value? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If V= 1/2mw^2(x^2 4y^2) for simple harmonic oscillator then find the corresponding Eigen value?.
If V= 1/2mw^2(x^2 4y^2) for simple harmonic oscillator then find the corresponding Eigen value? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about If V= 1/2mw^2(x^2 4y^2) for simple harmonic oscillator then find the corresponding Eigen value? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If V= 1/2mw^2(x^2 4y^2) for simple harmonic oscillator then find the corresponding Eigen value?.
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