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JEE Exam  >  JEE Questions  >  Passage IIA chiral organic compound A (C9H12O... Start Learning for Free
Passage II
A chiral organic compound A (C9H12O2) does not give positive Tollen's test or iodoform test. However, A on treatment with 1.0 equivalent of CH3MgBr followed by acid hydrolysis gives B (C10H16O2) which gives positive iodoform test. B on refluxing with aqueous Na2CO3 solution gives the following compound as major product.
Q. 
 What is the most probable structure of A ?
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
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Passage IIA chiral organic compound A (C9H12O2) does not give positive...
By carrying out the retro-aldol synthesis, the structure of B can be known as

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Passage IIA chiral organic compound A (C9H12O2) does not give positive...
By carrying out the retro-aldol synthesis, the structure of B can be known as
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Volumetric analysis is based on the principle of equivalence a that minloces lead in the ratio of their equivalents. At the equivalence point of the reaction, involving the reactahts A and B : Number of gram equivalents of A = Number of gram equivalents of B..If VA ml of solution A having normality NA react just completely with VB ml of solution B having normalityNB thenEquation(1), called normality equation is very useful in numerical of volumetric analysis. Equivalent masses of different substances :Basically the equivalent mass of a substance is defined as the pads by seam ctituhich combine with or displace 1.0078 parts (1part) by mass of hydrogen, 8 parts by mansetaisiosaid 35.5 parts by mass of chlorine.Mass of a substance expressed in gram equal to its equivalent man is gam equivalent mass. Equivalent mass of a substance is not constant but depends upon the maw i malice the substance participates.Equivalent mass of an acid in acid-base reaction is its mass in grannehidicodoinisooleaf replaceable Fi ions (= 1.0078 g1g).0n the other hand, equivalent mass of a bagels istolonellfacontairis 1 mole of replaceable 0H ions. 1 g equivalent mass each of an acid and base an ionclinegins saint and 1 mole of water= 18 g). Equivalent mass of an oxidising agent is its mass which gains 1 mole at ellecismitcan be obtained by dividing the molecular mass or formula mass by the total decrease in aididditaiiilberef one or more elements per molecule.0n the other hand, equivalent mass of a reducing agent is the mass of the substance which loses 1 mole of electorns. It can be calculated by dividing the molecular or formula mass of the subtance by the total increase in oxidation number of one or more elements per molecular or formula mass.Q.Which of the following solutions, when mixed with 100 ml of 0.05 M NaOH, will give a neutral solution?

Volumetric analysis is based on the principle of equivalence a that minloces lead in the ratio of their equivalents. At the equivalence point of the reaction, involving the reactahts A and B : Number of gram equivalents of A = Number of gram equivalents of B..If VA ml of solution A having normality NA react just completely with VB ml of solution B having normalityNB thenEquation(1), called normality equation is very useful in numerical of volumetric analysis. Equivalent masses of different substances :Basically the equivalent mass of a substance is defined as the pads by seam ctituhich combine with or displace 1.0078 parts (1part) by mass of hydrogen, 8 parts by mansetaisiosaid 35.5 parts by mass of chlorine.Mass of a substance expressed in gram equal to its equivalent man is gam equivalent mass. Equivalent mass of a substance is not constant but depends upon the maw i malice the substance participates.Equivalent mass of an acid in acid-base reaction is its mass in grannehidicodoinisooleaf replaceable Fi ions (= 1.0078 g1g).0n the other hand, equivalent mass of a bagels istolonellfacontairis 1 mole of replaceable 0H ions. 1 g equivalent mass each of an acid and base an ionclinegins saint and 1 mole of water= 18 g). Equivalent mass of an oxidising agent is its mass which gains 1 mole at ellecismitcan be obtained by dividing the molecular mass or formula mass by the total decrease in aididditaiiilberef one or more elements per molecule.0n the other hand, equivalent mass of a reducing agent is the mass of the substance which loses 1 mole of electorns. It can be calculated by dividing the molecular or formula mass of the subtance by the total increase in oxidation number of one or more elements per molecular or formula mass.Q.9.8 g of an acid on treatment with excess of an alkali forms salt along with 3.6 g of water. What is the equivalent mass of the acid?

Volumetric analysis is based on the principle of equivalence a that minloces lead in the ratio of their equivalents. At the equivalence point of the reaction, involving the reactahts A and B : Number of gram equivalents of A = Number of gram equivalents of B..If VA ml of solution A having normality NA react just completely with VB ml of solution B having normalityNB thenEquation(1), called normality equation is very useful in numerical of volumetric analysis. Equivalent masses of different substances :Basically the equivalent mass of a substance is defined as the pads by seam ctituhich combine with or displace 1.0078 parts (1part) by mass of hydrogen, 8 parts by mansetaisiosaid 35.5 parts by mass of chlorine.Mass of a substance expressed in gram equal to its equivalent man is gam equivalent mass. Equivalent mass of a substance is not constant but depends upon the maw i malice the substance participates.Equivalent mass of an acid in acid-base reaction is its mass in grannehidicodoinisooleaf replaceable Fi ions (= 1.0078 g1g).0n the other hand, equivalent mass of a bagels istolonellfacontairis 1 mole of replaceable 0H ions. 1 g equivalent mass each of an acid and base an ionclinegins saint and 1 mole of water= 18 g). Equivalent mass of an oxidising agent is its mass which gains 1 mole at ellecismitcan be obtained by dividing the molecular mass or formula mass by the total decrease in aididditaiiilberef one or more elements per molecule.0n the other hand, equivalent mass of a reducing agent is the mass of the substance which loses 1 mole of electorns. It can be calculated by dividing the molecular or formula mass of the subtance by the total increase in oxidation number of one or more elements per molecular or formula mass.Q.100 ml of 0.1 M H3 P02 is titrated with 0.1 M NaOH. The volume of NaOH needed will be

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Passage IIA chiral organic compound A (C9H12O2) does not give positive Tollens test or iodoform test. However, A on treatment with 1.0 equivalent of CH3MgBr followed by acid hydrolysis gives B (C10H16O2) which gives positive iodoform test. B on refluxing with aqueous Na2CO3 solution gives the following compound as major product.Q.What is the most probable structure of A ?a)b)c)d)Correct answer is option 'C'. Can you explain this answer?
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Passage IIA chiral organic compound A (C9H12O2) does not give positive Tollens test or iodoform test. However, A on treatment with 1.0 equivalent of CH3MgBr followed by acid hydrolysis gives B (C10H16O2) which gives positive iodoform test. B on refluxing with aqueous Na2CO3 solution gives the following compound as major product.Q.What is the most probable structure of A ?a)b)c)d)Correct answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Passage IIA chiral organic compound A (C9H12O2) does not give positive Tollens test or iodoform test. However, A on treatment with 1.0 equivalent of CH3MgBr followed by acid hydrolysis gives B (C10H16O2) which gives positive iodoform test. B on refluxing with aqueous Na2CO3 solution gives the following compound as major product.Q.What is the most probable structure of A ?a)b)c)d)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Passage IIA chiral organic compound A (C9H12O2) does not give positive Tollens test or iodoform test. However, A on treatment with 1.0 equivalent of CH3MgBr followed by acid hydrolysis gives B (C10H16O2) which gives positive iodoform test. B on refluxing with aqueous Na2CO3 solution gives the following compound as major product.Q.What is the most probable structure of A ?a)b)c)d)Correct answer is option 'C'. Can you explain this answer?.
Solutions for Passage IIA chiral organic compound A (C9H12O2) does not give positive Tollens test or iodoform test. However, A on treatment with 1.0 equivalent of CH3MgBr followed by acid hydrolysis gives B (C10H16O2) which gives positive iodoform test. B on refluxing with aqueous Na2CO3 solution gives the following compound as major product.Q.What is the most probable structure of A ?a)b)c)d)Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Passage IIA chiral organic compound A (C9H12O2) does not give positive Tollens test or iodoform test. However, A on treatment with 1.0 equivalent of CH3MgBr followed by acid hydrolysis gives B (C10H16O2) which gives positive iodoform test. B on refluxing with aqueous Na2CO3 solution gives the following compound as major product.Q.What is the most probable structure of A ?a)b)c)d)Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Passage IIA chiral organic compound A (C9H12O2) does not give positive Tollens test or iodoform test. However, A on treatment with 1.0 equivalent of CH3MgBr followed by acid hydrolysis gives B (C10H16O2) which gives positive iodoform test. B on refluxing with aqueous Na2CO3 solution gives the following compound as major product.Q.What is the most probable structure of A ?a)b)c)d)Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Passage IIA chiral organic compound A (C9H12O2) does not give positive Tollens test or iodoform test. However, A on treatment with 1.0 equivalent of CH3MgBr followed by acid hydrolysis gives B (C10H16O2) which gives positive iodoform test. B on refluxing with aqueous Na2CO3 solution gives the following compound as major product.Q.What is the most probable structure of A ?a)b)c)d)Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Passage IIA chiral organic compound A (C9H12O2) does not give positive Tollens test or iodoform test. However, A on treatment with 1.0 equivalent of CH3MgBr followed by acid hydrolysis gives B (C10H16O2) which gives positive iodoform test. B on refluxing with aqueous Na2CO3 solution gives the following compound as major product.Q.What is the most probable structure of A ?a)b)c)d)Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Passage IIA chiral organic compound A (C9H12O2) does not give positive Tollens test or iodoform test. However, A on treatment with 1.0 equivalent of CH3MgBr followed by acid hydrolysis gives B (C10H16O2) which gives positive iodoform test. B on refluxing with aqueous Na2CO3 solution gives the following compound as major product.Q.What is the most probable structure of A ?a)b)c)d)Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
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