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An organic compound X produces Y in the first step of oxidation which on further oxidation gave an acid. Y on treatment with ammoniacal silver nitrate solution gave a black precipitate. X is likely to be a
- a)1° alcohol
- b)3° alcohol
- c)Ethanal
- d)2-propanone
Correct answer is option 'A'. Can you explain this answer?
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An organic compound X produces Y in the first step of oxidation which ...
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An organic compound X produces Y in the first step of oxidation which ...
The given information:
An organic compound X produces Y in the first step of oxidation, which on further oxidation gives an acid. Y, when treated with ammoniacal silver nitrate solution, gives a black precipitate.
Analysis of the given information:
From the given information, we can infer the following:
- Compound X is oxidized to produce compound Y.
- Compound Y, upon further oxidation, forms an acid.
- Compound Y gives a black precipitate when treated with ammoniacal silver nitrate solution.
Explanation:
To determine the likely identity of compound X, we need to analyze the given information step by step.
Step 1: Oxidation of compound X
Since compound X is oxidized to produce compound Y, it suggests that compound X contains a functional group that can be oxidized. One such functional group is the -OH group present in alcohols.
Step 2: Further oxidation of compound Y
The fact that compound Y, which is produced from compound X, can be further oxidized to form an acid indicates that compound Y is an aldehyde. Aldehydes can undergo further oxidation to form carboxylic acids.
Step 3: Formation of black precipitate with ammoniacal silver nitrate
The black precipitate formed when compound Y is treated with ammoniacal silver nitrate solution indicates the presence of the Tollens' reagent test. This test is used to detect the presence of aldehydes. Aldehydes react with Tollens' reagent to form a silver mirror or a black precipitate of silver.
Conclusion:
Based on the given information and the analysis, it can be concluded that compound X is likely to be a 1 alcohol. 1 alcohols can be oxidized to form aldehydes, which further oxidize to carboxylic acids. The formation of a black precipitate with ammoniacal silver nitrate confirms the presence of an aldehyde, which supports the identification of compound X as a 1 alcohol.
An organic compound X produces Y in the first step of oxidation, which on further oxidation gives an acid. Y, when treated with ammoniacal silver nitrate solution, gives a black precipitate.
Analysis of the given information:
From the given information, we can infer the following:
- Compound X is oxidized to produce compound Y.
- Compound Y, upon further oxidation, forms an acid.
- Compound Y gives a black precipitate when treated with ammoniacal silver nitrate solution.
Explanation:
To determine the likely identity of compound X, we need to analyze the given information step by step.
Step 1: Oxidation of compound X
Since compound X is oxidized to produce compound Y, it suggests that compound X contains a functional group that can be oxidized. One such functional group is the -OH group present in alcohols.
Step 2: Further oxidation of compound Y
The fact that compound Y, which is produced from compound X, can be further oxidized to form an acid indicates that compound Y is an aldehyde. Aldehydes can undergo further oxidation to form carboxylic acids.
Step 3: Formation of black precipitate with ammoniacal silver nitrate
The black precipitate formed when compound Y is treated with ammoniacal silver nitrate solution indicates the presence of the Tollens' reagent test. This test is used to detect the presence of aldehydes. Aldehydes react with Tollens' reagent to form a silver mirror or a black precipitate of silver.
Conclusion:
Based on the given information and the analysis, it can be concluded that compound X is likely to be a 1 alcohol. 1 alcohols can be oxidized to form aldehydes, which further oxidize to carboxylic acids. The formation of a black precipitate with ammoniacal silver nitrate confirms the presence of an aldehyde, which supports the identification of compound X as a 1 alcohol.
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An organic compound X produces Y in the first step of oxidation which on further oxidation gave an acid. Y on treatment with ammoniacal silver nitrate solution gave a black precipitate. X is likely to be a a)1 alcoholb)3 alcoholc)Ethanald)2-propanoneCorrect answer is option 'A'. Can you explain this answer?
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An organic compound X produces Y in the first step of oxidation which on further oxidation gave an acid. Y on treatment with ammoniacal silver nitrate solution gave a black precipitate. X is likely to be a a)1 alcoholb)3 alcoholc)Ethanald)2-propanoneCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An organic compound X produces Y in the first step of oxidation which on further oxidation gave an acid. Y on treatment with ammoniacal silver nitrate solution gave a black precipitate. X is likely to be a a)1 alcoholb)3 alcoholc)Ethanald)2-propanoneCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound X produces Y in the first step of oxidation which on further oxidation gave an acid. Y on treatment with ammoniacal silver nitrate solution gave a black precipitate. X is likely to be a a)1 alcoholb)3 alcoholc)Ethanald)2-propanoneCorrect answer is option 'A'. Can you explain this answer?.
An organic compound X produces Y in the first step of oxidation which on further oxidation gave an acid. Y on treatment with ammoniacal silver nitrate solution gave a black precipitate. X is likely to be a a)1 alcoholb)3 alcoholc)Ethanald)2-propanoneCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An organic compound X produces Y in the first step of oxidation which on further oxidation gave an acid. Y on treatment with ammoniacal silver nitrate solution gave a black precipitate. X is likely to be a a)1 alcoholb)3 alcoholc)Ethanald)2-propanoneCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound X produces Y in the first step of oxidation which on further oxidation gave an acid. Y on treatment with ammoniacal silver nitrate solution gave a black precipitate. X is likely to be a a)1 alcoholb)3 alcoholc)Ethanald)2-propanoneCorrect answer is option 'A'. Can you explain this answer?.
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