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Passage IA and B are two structural isomers with their molecular formula C7H14Oand both gives-off effervescence on heating with Na-metal. However, neither A nor B decolourise brown colour of Br2-H2O. Treating either A or Bwith hot conc, sulphuric acid solution results in the form ation of the same compound C (C7H12). C on treatment with O3 followed by Zn-H2Ogives D (C7H12O2). D gives E (C7H16O2) on treatm ent with NaBH4. E has only one methyl group and forms yellow ppt with I2/KOH. Also, A gives delayed turbidity on treatment with conc. HCI/ZnCI2 while B gives immediate turbidity on similar treatment.Q.Which of the following statement regarding A and B is incorrect?a)Only A will change the colour of dichromate solution not Bb)C on reactionwith (CH3COO)2Hg/H2Ofollowed by NaBH4 gives Bc)C on treatment with B2H6/H2O2 followed by alkaline work-up gives Ad)Treating either A or 8 with SOCI2 followed by the reduction with LiAIH4 results in the formation of same productCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Passage IA and B are two structural isomers with their molecular formula C7H14Oand both gives-off effervescence on heating with Na-metal. However, neither A nor B decolourise brown colour of Br2-H2O. Treating either A or Bwith hot conc, sulphuric acid solution results in the form ation of the same compound C (C7H12). C on treatment with O3 followed by Zn-H2Ogives D (C7H12O2). D gives E (C7H16O2) on treatm ent with NaBH4. E has only one methyl group and forms yellow ppt with I2/KOH. Also, A gives delayed turbidity on treatment with conc. HCI/ZnCI2 while B gives immediate turbidity on similar treatment.Q.Which of the following statement regarding A and B is incorrect?a)Only A will change the colour of dichromate solution not Bb)C on reactionwith (CH3COO)2Hg/H2Ofollowed by NaBH4 gives Bc)C on treatment with B2H6/H2O2 followed by alkaline work-up gives Ad)Treating either A or 8 with SOCI2 followed by the reduction with LiAIH4 results in the formation of same productCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Passage IA and B are two structural isomers with their molecular formula C7H14Oand both gives-off effervescence on heating with Na-metal. However, neither A nor B decolourise brown colour of Br2-H2O. Treating either A or Bwith hot conc, sulphuric acid solution results in the form ation of the same compound C (C7H12). C on treatment with O3 followed by Zn-H2Ogives D (C7H12O2). D gives E (C7H16O2) on treatm ent with NaBH4. E has only one methyl group and forms yellow ppt with I2/KOH. Also, A gives delayed turbidity on treatment with conc. HCI/ZnCI2 while B gives immediate turbidity on similar treatment.Q.Which of the following statement regarding A and B is incorrect?a)Only A will change the colour of dichromate solution not Bb)C on reactionwith (CH3COO)2Hg/H2Ofollowed by NaBH4 gives Bc)C on treatment with B2H6/H2O2 followed by alkaline work-up gives Ad)Treating either A or 8 with SOCI2 followed by the reduction with LiAIH4 results in the formation of same productCorrect answer is option 'B'. Can you explain this answer?.

Solutions for Passage IA and B are two structural isomers with their molecular formula C7H14Oand both gives-off effervescence on heating with Na-metal. However, neither A nor B decolourise brown colour of Br2-H2O. Treating either A or Bwith hot conc, sulphuric acid solution results in the form ation of the same compound C (C7H12). C on treatment with O3 followed by Zn-H2Ogives D (C7H12O2). D gives E (C7H16O2) on treatm ent with NaBH4. E has only one methyl group and forms yellow ppt with I2/KOH. Also, A gives delayed turbidity on treatment with conc. HCI/ZnCI2 while B gives immediate turbidity on similar treatment.Q.Which of the following statement regarding A and B is incorrect?a)Only A will change the colour of dichromate solution not Bb)C on reactionwith (CH3COO)2Hg/H2Ofollowed by NaBH4 gives Bc)C on treatment with B2H6/H2O2 followed by alkaline work-up gives Ad)Treating either A or 8 with SOCI2 followed by the reduction with LiAIH4 results in the formation of same productCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Passage IA and B are two structural isomers with their molecular formula C7H14Oand both gives-off effervescence on heating with Na-metal. However, neither A nor B decolourise brown colour of Br2-H2O. Treating either A or Bwith hot conc, sulphuric acid solution results in the form ation of the same compound C (C7H12). C on treatment with O3 followed by Zn-H2Ogives D (C7H12O2). D gives E (C7H16O2) on treatm ent with NaBH4. E has only one methyl group and forms yellow ppt with I2/KOH. Also, A gives delayed turbidity on treatment with conc. HCI/ZnCI2 while B gives immediate turbidity on similar treatment.Q.Which of the following statement regarding A and B is incorrect?a)Only A will change the colour of dichromate solution not Bb)C on reactionwith (CH3COO)2Hg/H2Ofollowed by NaBH4 gives Bc)C on treatment with B2H6/H2O2 followed by alkaline work-up gives Ad)Treating either A or 8 with SOCI2 followed by the reduction with LiAIH4 results in the formation of same productCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Passage IA and B are two structural isomers with their molecular formula C7H14Oand both gives-off effervescence on heating with Na-metal. However, neither A nor B decolourise brown colour of Br2-H2O. Treating either A or Bwith hot conc, sulphuric acid solution results in the form ation of the same compound C (C7H12). C on treatment with O3 followed by Zn-H2Ogives D (C7H12O2). D gives E (C7H16O2) on treatm ent with NaBH4. E has only one methyl group and forms yellow ppt with I2/KOH. Also, A gives delayed turbidity on treatment with conc. HCI/ZnCI2 while B gives immediate turbidity on similar treatment.Q.Which of the following statement regarding A and B is incorrect?a)Only A will change the colour of dichromate solution not Bb)C on reactionwith (CH3COO)2Hg/H2Ofollowed by NaBH4 gives Bc)C on treatment with B2H6/H2O2 followed by alkaline work-up gives Ad)Treating either A or 8 with SOCI2 followed by the reduction with LiAIH4 results in the formation of same productCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Passage IA and B are two structural isomers with their molecular formula C7H14Oand both gives-off effervescence on heating with Na-metal. However, neither A nor B decolourise brown colour of Br2-H2O. Treating either A or Bwith hot conc, sulphuric acid solution results in the form ation of the same compound C (C7H12). C on treatment with O3 followed by Zn-H2Ogives D (C7H12O2). D gives E (C7H16O2) on treatm ent with NaBH4. E has only one methyl group and forms yellow ppt with I2/KOH. Also, A gives delayed turbidity on treatment with conc. HCI/ZnCI2 while B gives immediate turbidity on similar treatment.Q.Which of the following statement regarding A and B is incorrect?a)Only A will change the colour of dichromate solution not Bb)C on reactionwith (CH3COO)2Hg/H2Ofollowed by NaBH4 gives Bc)C on treatment with B2H6/H2O2 followed by alkaline work-up gives Ad)Treating either A or 8 with SOCI2 followed by the reduction with LiAIH4 results in the formation of same productCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Passage IA and B are two structural isomers with their molecular formula C7H14Oand both gives-off effervescence on heating with Na-metal. However, neither A nor B decolourise brown colour of Br2-H2O. Treating either A or Bwith hot conc, sulphuric acid solution results in the form ation of the same compound C (C7H12). C on treatment with O3 followed by Zn-H2Ogives D (C7H12O2). D gives E (C7H16O2) on treatm ent with NaBH4. E has only one methyl group and forms yellow ppt with I2/KOH. Also, A gives delayed turbidity on treatment with conc. HCI/ZnCI2 while B gives immediate turbidity on similar treatment.Q.Which of the following statement regarding A and B is incorrect?a)Only A will change the colour of dichromate solution not Bb)C on reactionwith (CH3COO)2Hg/H2Ofollowed by NaBH4 gives Bc)C on treatment with B2H6/H2O2 followed by alkaline work-up gives Ad)Treating either A or 8 with SOCI2 followed by the reduction with LiAIH4 results in the formation of same productCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Passage IA and B are two structural isomers with their molecular formula C7H14Oand both gives-off effervescence on heating with Na-metal. However, neither A nor B decolourise brown colour of Br2-H2O. Treating either A or Bwith hot conc, sulphuric acid solution results in the form ation of the same compound C (C7H12). C on treatment with O3 followed by Zn-H2Ogives D (C7H12O2). D gives E (C7H16O2) on treatm ent with NaBH4. E has only one methyl group and forms yellow ppt with I2/KOH. Also, A gives delayed turbidity on treatment with conc. HCI/ZnCI2 while B gives immediate turbidity on similar treatment.Q.Which of the following statement regarding A and B is incorrect?a)Only A will change the colour of dichromate solution not Bb)C on reactionwith (CH3COO)2Hg/H2Ofollowed by NaBH4 gives Bc)C on treatment with B2H6/H2O2 followed by alkaline work-up gives Ad)Treating either A or 8 with SOCI2 followed by the reduction with LiAIH4 results in the formation of same productCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.