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The reaction of white phosphorus with aqueous NaOH gives phosphine along with another phosphorus containing compound. The reaction type; the oxidation states of phosphorus in phosphine and the other product respectively are 
  • a)
    redox reaction; - 3 and - 5
  • b)
    redox reaction; - 3 and + 5
  • c)
    disproportionation reaction; - 3 and + 5
  • d)
    disproportionation reaction; - 3 and - 5
Correct answer is option 'C'. Can you explain this answer?
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The reaction of white phosphorus with aqueous NaOH gives phosphine alo...
Reaction Type: Disproportionation Reaction

In a disproportionation reaction, a single compound undergoes both oxidation and reduction simultaneously. In this case, white phosphorus (P4) is reacting with aqueous NaOH (sodium hydroxide) to produce phosphine (PH3) and another phosphorus-containing compound.

Oxidation States of Phosphorus: -3 and +5

In phosphine (PH3), the oxidation state of phosphorus is -3. This is because hydrogen (H) has an oxidation state of +1, and there are three hydrogen atoms bonded to the phosphorus atom. Therefore, the overall charge on the compound is 0, so the oxidation state of phosphorus must be -3.

In the other phosphorus-containing compound, the oxidation state of phosphorus is +5. This is because the compound is formed when white phosphorus (P4) reacts with NaOH, which is a strong base that can hydrolyze P4 to produce the compound NaH2PO2 and H2 gas. In this compound, the oxidation state of phosphorus is +5 because it is bonded to two oxygen atoms, which have an oxidation state of -2 each. Therefore, the overall charge on the compound is -1, so the oxidation state of phosphorus must be +5.

Conclusion

The reaction of white phosphorus with aqueous NaOH is a disproportionation reaction, where phosphorus is simultaneously oxidized and reduced. The oxidation states of phosphorus in phosphine and the other phosphorus-containing compound are -3 and +5, respectively.
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The reaction of white phosphorus with aqueous NaOH gives phosphine alo...
The reaction of white phosphorus with aqueous alkali is

In the above reaction, phosphorus is simultaneously oxidised 

Therefore, this is an example of disproportionation reaction. Oxidation number of phosphorus in PH3 is - 3 and in NaH2PO2 is +1. However, +1 oxidation number is not given in any option, one might think that NaH2PO2 has gone to further decom positio n on heating.
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The reaction of white phosphorus with aqueous NaOH gives phosphine along with another phosphorus containing compound. The reaction type; the oxidation states of phosphorus in phosphine and the other product respectively area)redox reaction; - 3 and - 5b)redox reaction; - 3 and + 5c)disproportionation reaction; - 3 and + 5d)disproportionation reaction; - 3 and -5Correct answer is option 'C'. Can you explain this answer?
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The reaction of white phosphorus with aqueous NaOH gives phosphine along with another phosphorus containing compound. The reaction type; the oxidation states of phosphorus in phosphine and the other product respectively area)redox reaction; - 3 and - 5b)redox reaction; - 3 and + 5c)disproportionation reaction; - 3 and + 5d)disproportionation reaction; - 3 and -5Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The reaction of white phosphorus with aqueous NaOH gives phosphine along with another phosphorus containing compound. The reaction type; the oxidation states of phosphorus in phosphine and the other product respectively area)redox reaction; - 3 and - 5b)redox reaction; - 3 and + 5c)disproportionation reaction; - 3 and + 5d)disproportionation reaction; - 3 and -5Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The reaction of white phosphorus with aqueous NaOH gives phosphine along with another phosphorus containing compound. The reaction type; the oxidation states of phosphorus in phosphine and the other product respectively area)redox reaction; - 3 and - 5b)redox reaction; - 3 and + 5c)disproportionation reaction; - 3 and + 5d)disproportionation reaction; - 3 and -5Correct answer is option 'C'. Can you explain this answer?.
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