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Two vessels A and B of equal capacities contain mixtures of milk and water in the ratios 4 : 1 and 3 : 1, respectively. 25% of the mixture from A is taken out and added to B. After mixing it thoroughly, an equal amount is taken out from B and added back to A. The ratio of milk to water in vessel A after the second operation is:
  • a)
    79 : 21
  • b)
    83 : 17
  • c)
    77 : 23
  • d)
    81 : 19
  • e)
    77 : 79
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Two vessels A and B of equal capacities contain mixtures of milk and ...
Consider 40 Liters in both vessels.
A has 32 liters of Milk, 8 liters of water
B has 30 liters of Mils, 10 liters of water
25% of A has 8 liters of Milk, 2 liters of water
B now has 38 liters of Milk and 12 liters of water.
Now 10 liters of B 38/5 = 7.6 liters of milk and 2.4 liters of water
A will have 24 + 7.6 = 31.6 liters of Milk, 6+2.4 = 8.4 liters of water.
Ratio = 31.6:8.4 = 316:84 = 79:21
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Most Upvoted Answer
Two vessels A and B of equal capacities contain mixtures of milk and ...
Given Information:

- The ratio of milk and water in vessel A is 4:1.
- The ratio of milk and water in vessel B is 3:1.
- 25% of the mixture from vessel A is taken out and added to vessel B.
- An equal amount is taken out from vessel B and added back to vessel A.

To Find:

- The ratio of milk to water in vessel A after the second operation.

Solution:

Step 1: Assume the initial quantity of mixture in vessel A and vessel B to be 4x and 3x, respectively.

Step 2: After mixing, the quantity of mixture in vessel B becomes (3x + x) = 4x.

Step 3: The quantity of mixture taken from vessel A = 25% of 4x = x.

Step 4: The quantity of mixture in vessel A after the first operation = 4x - x = 3x.

Step 5: The quantity of mixture taken from vessel B = x.

Step 6: The quantity of mixture in vessel B after the second operation = 4x - x = 3x.

Step 7: The quantity of mixture added back to vessel A = x.

Step 8: The quantity of mixture in vessel A after the second operation = 3x + x = 4x.

Step 9: Let the quantity of milk in vessel A after the second operation be 4y and the quantity of water be y.

Step 10: The quantity of milk in vessel B after the second operation is 3/4 * 4x = 3x and the quantity of water is x.

Step 11: The quantity of milk in the mixture taken from vessel A = (4/5)*4y = 16y/5.

Step 12: The quantity of milk in the mixture added back to vessel A = (1/2)*3x = 3x/2.

Step 13: The total quantity of milk in vessel A after the second operation = 4y + 16y/5 - 3x/2.

Step 14: The total quantity of water in vessel A after the second operation = y + x - x/2 = (3/2)y.

Step 15: The ratio of milk to water in vessel A after the second operation = (4y + 16y/5 - 3x/2) : (3/2)y.

Step 16: Equating the quantity of mixture in vessel A before and after the operations, we get:

4x = 4y + (16/5)y - (3/2)x

Step 17: Simplifying the above equation, we get:

y/x = 1/5

Step 18: Substituting the value of y/x in the ratio obtained in step 15, we get:

(16 + 16/5 - 3/2) : (3/2) = 79 : 21

Therefore, the ratio of milk to water in vessel A after the second operation is 79 : 21.

Answer: (a) 79 : 21
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Two vessels A and B of equal capacities contain mixtures of milk and water in the ratios 4 : 1 and 3 : 1, respectively. 25% of the mixture from A is taken out and added to B. After mixing it thoroughly, an equal amount is taken out from B and added back to A. The ratio of milk to water in vessel A after the second operation is:a) 79 : 21b) 83 : 17c) 77 : 23d) 81 : 19e) 77 : 79Correct answer is option 'A'. Can you explain this answer?
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