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A train starting from rest attains a velocity of 72 kmh–1 in 5 minutes. Assuming that the acceleration is uniform, find (i) the acceleration and (ii)the distance travelled by the train for attaining this velocity.?
Most Upvoted Answer
A train starting from rest attains a velocity of 72 kmh–1 in 5 minutes...
Solution:

Given:

Initial velocity, u = 0 kmh–1

Final velocity, v = 72 kmh–1

Time taken, t = 5 min = 5/60 h

To find:

(i) Acceleration, a

(ii) Distance travelled, s

Formula used:

We know that,

v = u + at

s = ut + 1/2 at^2

Where,

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time taken

s = Distance travelled

Calculation:

(i) Acceleration, a

We know that,

v = u + at

a = (v - u) / t

Substituting the given values, we get

a = (72 - 0) / (5/60)

a = 86.4 kmh–2

Therefore, the acceleration of the train is 86.4 kmh–2.

(ii) Distance travelled, s

We know that,

s = ut + 1/2 at^2

Substituting the given values, we get

s = 0 x (5/60) + 1/2 x 86.4 x (5/60)^2

s = 0.3 km

Therefore, the distance travelled by the train to attain the velocity of 72 kmh–1 is 0.3 km.

Conclusion:

Thus, the acceleration of the train is 86.4 kmh–2 and the distance travelled by the train to attain the velocity of 72 kmh–1 is 0.3 km.
Community Answer
A train starting from rest attains a velocity of 72 kmh–1 in 5 minutes...
Here, u=0. v= 72km/h = 72× 5/18 = 20 m/s t= 5min = 300s

a= v- u / t 20- 0/ 300= 20 / 300 = 0.067m/s
^2
s= ut + 1/2 at^2. s= 0× t + 1/2 ×0.067×300×300. s = 1005m
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A train starting from rest attains a velocity of 72 kmh–1 in 5 minutes. Assuming that the acceleration is uniform, find (i) the acceleration and (ii)the distance travelled by the train for attaining this velocity.?
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