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DIRECTIONS for questions: Select the correct alternative from the given choices. There are two groups of workers, G1 and G2. There are 30 workers in G1 and 60 in G2. Each worker in G1 works three times as fast as any worker in G2. If all the workers in G1 together ploughed a certain field in half a day, then find the time taken by all the workers in G1 and G2 together to plough a field whose area is 50% more than that of the first field.
  • a)
    9 / 20 days
  • b)
    9 / 25 days
  • c)
    1 / 2 days
  • d)
    27 / 50
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
DIRECTIONS for questions: Select the correct alternative from the giv...
Let the rate at which each worker in G2 works be x units/day
Rate at which each worker in G1 works = 3x units/day
Let the area of the first field be w w = 30(3x)(0.5) = 45x
Area of second field = 1,5w = 67.5x
Let the required time be t days
∴ t[30(3x)+60(x)] = 67.5x
⇒ t = 67.5 / 150 = 9 / 20
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Most Upvoted Answer
DIRECTIONS for questions: Select the correct alternative from the giv...
Given:
- There are two groups of workers, G1 and G2.
- There are 30 workers in G1 and 60 in G2.
- Each worker in G1 works three times as fast as any worker in G2.
- All the workers in G1 together ploughed a certain field in half a day.

To Find:
The time taken by all the workers in G1 and G2 together to plough a field whose area is 50% more than that of the first field.

Approach:
Let's assume that each worker in G2 ploughs an area of "x" in one day. Therefore, each worker in G1 ploughs an area of "3x" in one day.

We are given that all the workers in G1 together ploughed a certain field in half a day. Therefore, the total area of the field ploughed by G1 workers in half a day is:
Area ploughed by G1 workers = 30 * (3x) * (1/2) = 45x

Now, we need to find the time taken by all the workers in G1 and G2 together to plough a field whose area is 50% more than that of the first field.

Solution:

Step 1: Find the total area of the first field.
Area of the first field = 45x

Step 2: Find the area of the field whose area is 50% more than the first field.
Area of the second field = 1.5 * (Area of the first field) = 1.5 * (45x) = 67.5x

Step 3: Find the time taken by all the workers in G1 and G2 together to plough the second field.
Total number of workers in G1 and G2 = 30 + 60 = 90
Area ploughed by G1 and G2 workers in one day = 30 * (3x) + 60 * x = 90x + 60x = 150x
Time taken by all the workers in G1 and G2 together to plough the second field = (Area of the second field) / (Area ploughed by G1 and G2 workers in one day) = (67.5x) / (150x) = 9/20 days

Therefore, the correct answer is option 'A' - 9/20 days.
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DIRECTIONS for questions: Select the correct alternative from the given choices. There are two groups of workers, G1 and G2. There are 30 workers in G1 and 60 in G2. Each worker in G1 works three times as fast as any worker in G2. If all the workers in G1 together ploughed a certain field in half a day, then find the time taken by all the workers in G1 and G2 together to plough a field whose area is 50% more than that of the first field.a) 9 / 20 daysb) 9 / 25 daysc) 1 / 2 daysd) 27 / 50Correct answer is option 'A'. Can you explain this answer?
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