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What is the maximum electric field when Vbi = 2V, VR = 5V and width of the semiconductor is 7cm? 
  • a)
    -100V/m 
  • b)
    100V/m 
  • c)
    200V/m
  • d)
    -200V/m 
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
What is the maximum electric field when Vbi = 2V, VR = 5V and width of...
Emax = -2(Vbi + VR) / W
= -2(2 + 5) / (7 * 10-2)
= -200V/m.
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Community Answer
What is the maximum electric field when Vbi = 2V, VR = 5V and width of...
To solve this problem, we need to understand the relationship between electric field, potential difference, and width of the semiconductor.

1. Equation for electric field:
The electric field (E) is given by the equation E = V/d, where V is the potential difference and d is the width of the semiconductor.

2. Given values:
Vbi = 2V (built-in potential)
VR = 5V (applied potential)
Width of the semiconductor = 7cm

3. Calculation:
a) Electric field due to built-in potential:
Using the equation E = V/d, we can calculate the electric field due to the built-in potential: Ebi = Vbi/d

Ebi = 2V/7cm

b) Electric field due to applied potential:
Using the equation E = V/d, we can calculate the electric field due to the applied potential: ER = VR/d

ER = 5V/7cm

c) Total electric field:
The total electric field is the sum of the electric fields due to the built-in potential and the applied potential: Etotal = Ebi + ER

Etotal = Ebi + ER
= 2V/7cm + 5V/7cm
= (2V + 5V)/7cm
= 7V/7cm
= 1V/cm

d) Converting to SI units:
The question asks for the maximum electric field, so we need to convert 1V/cm to SI units (V/m).

1V/cm = 100V/m

Therefore, the maximum electric field is 100V/m, which corresponds to option D.
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What is the maximum electric field when Vbi = 2V, VR = 5V and width of the semiconductor is 7cm?a)-100V/mb)100V/mc)200V/md)-200V/mCorrect answer is option 'D'. Can you explain this answer?
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