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Max z = 40x1 + 60x2
s/t: 2x + y ≤ 90
x + y ≤ 50
x + 2y ≤ 80
x, y ≥ 0
Find the value of zmax
- a)2400
- b)2400
- c)alternative optimal
- d)unique
- e)multiple
Correct answer is between ' 2400, 2400'. Can you explain this answer?
Verified Answer
Max z = 40x1 + 60x2 s/t: 2x + y ≤ 90x + y ≤ 50x + 2y ≤ 80x, y ≥ 0Find...
zA = (0, 1) = 2
zB = (0, 2) = 4∗
zC = (2, 3) = 4∗
Most Upvoted Answer
Max z = 40x1 + 60x2 s/t: 2x + y ≤ 90x + y ≤ 50x + 2y ≤ 80x, y ≥ 0Find...
Explanation:
Objective Function:
- Max z = 40x1 + 60x2
Constraints:
1. 2x + y ≤ 90
2. x + y ≤ 50
3. x + 2y ≤ 80
4. x, y ≥ 0
Analysis:
- To find the maximum value of z, we need to optimize the objective function while satisfying all the given constraints.
- The given constraints form a feasible region in the x-y plane.
- By solving the system of inequalities, we can identify the feasible region and determine the corner points.
Corner Points:
- A: (0, 0)
- B: (40, 0)
- C: (20, 30)
- D: (0, 40)
Optimal Solution:
- By evaluating the objective function at each corner point, we find that the maximum value of z (zmax) occurs at point C (20, 30).
- Substitute x = 20 and y = 30 into the objective function: zmax = 40(20) + 60(30) = 2400
Therefore, the correct answer is 2400.
Objective Function:
- Max z = 40x1 + 60x2
Constraints:
1. 2x + y ≤ 90
2. x + y ≤ 50
3. x + 2y ≤ 80
4. x, y ≥ 0
Analysis:
- To find the maximum value of z, we need to optimize the objective function while satisfying all the given constraints.
- The given constraints form a feasible region in the x-y plane.
- By solving the system of inequalities, we can identify the feasible region and determine the corner points.
Corner Points:
- A: (0, 0)
- B: (40, 0)
- C: (20, 30)
- D: (0, 40)
Optimal Solution:
- By evaluating the objective function at each corner point, we find that the maximum value of z (zmax) occurs at point C (20, 30).
- Substitute x = 20 and y = 30 into the objective function: zmax = 40(20) + 60(30) = 2400
Therefore, the correct answer is 2400.
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Community Answer
Max z = 40x1 + 60x2 s/t: 2x + y ≤ 90x + y ≤ 50x + 2y ≤ 80x, y ≥ 0Find...
zA = (0, 1) = 2
zB = (0, 2) = 4∗
zC = (2, 3) = 4∗
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Max z = 40x1 + 60x2 s/t: 2x + y ≤ 90x + y ≤ 50x + 2y ≤ 80x, y ≥ 0Find the value of zmaxa) 2400b) 2400c) alternative optimald) uniquee) multipleCorrect answer is between ' 2400, 2400'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Max z = 40x1 + 60x2 s/t: 2x + y ≤ 90x + y ≤ 50x + 2y ≤ 80x, y ≥ 0Find the value of zmaxa) 2400b) 2400c) alternative optimald) uniquee) multipleCorrect answer is between ' 2400, 2400'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Max z = 40x1 + 60x2 s/t: 2x + y ≤ 90x + y ≤ 50x + 2y ≤ 80x, y ≥ 0Find the value of zmaxa) 2400b) 2400c) alternative optimald) uniquee) multipleCorrect answer is between ' 2400, 2400'. Can you explain this answer?.
Max z = 40x1 + 60x2 s/t: 2x + y ≤ 90x + y ≤ 50x + 2y ≤ 80x, y ≥ 0Find the value of zmaxa) 2400b) 2400c) alternative optimald) uniquee) multipleCorrect answer is between ' 2400, 2400'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Max z = 40x1 + 60x2 s/t: 2x + y ≤ 90x + y ≤ 50x + 2y ≤ 80x, y ≥ 0Find the value of zmaxa) 2400b) 2400c) alternative optimald) uniquee) multipleCorrect answer is between ' 2400, 2400'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Max z = 40x1 + 60x2 s/t: 2x + y ≤ 90x + y ≤ 50x + 2y ≤ 80x, y ≥ 0Find the value of zmaxa) 2400b) 2400c) alternative optimald) uniquee) multipleCorrect answer is between ' 2400, 2400'. Can you explain this answer?.
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