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Find the HCF and LCM of the following integers by applying the prime factorization method 40, 36 and 126.
  • a)
    2, 2520
  • b)
    2, 2525
  • c)
    2, 2530
  • d)
    2, 2535
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Find the HCF and LCM of the following integers by applying the prime ...
40 = 2 x 2 x 2 x 5 = 23 x 5
36 = 2 x 2 x 3 x 3 = 22 x 32
and 126 = 2 x 3 x 3 x 7 = 2 x 32 x 7
For H.C.F taking minimum power of common factor H.C.F = (2)1 = 2
For L.C.M, taking maximum power of prime factors LC.M = 23 x 32 x 5 x 7 = 8 x 9 x 5 x 7 = 2520
Hence, H.C.F = 2 L.C.M = 2520
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Most Upvoted Answer
Find the HCF and LCM of the following integers by applying the prime ...
Prime Factorization Method for Finding HCF and LCM

Prime Factorization of the Given Integers:
- 40 = 2^3 * 5
- 36 = 2^2 * 3^2
- 126 = 2 * 3^2 * 7

Finding HCF:
- The highest common factor (HCF) is the product of the common prime factors with the lowest powers.
- HCF = 2^2 * 3 = 4 * 3 = 12

Finding LCM:
- The lowest common multiple (LCM) is the product of all the prime factors with the highest powers.
- LCM = 2^3 * 3^2 * 5 * 7 = 8 * 9 * 5 * 7 = 2520
Therefore, the HCF and LCM of 40, 36, and 126 are 12 and 2520 respectively.
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Find the HCF and LCM of the following integers by applying the prime factorization method 40, 36 and 126.a)2, 2520b)2, 2525c)2, 2530d)2, 2535Correct answer is option 'A'. Can you explain this answer?
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