Civil Engineering (CE) Exam > Civil Engineering (CE) Questions > What is the intensity of pressure (in MPa) ...
Start Learning for Free
What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).
Correct answer is '15.1 to 15.2'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
What is the intensity of pressure (in MPa) in the ocean at a depth o...
By hydro-static law
dp / dh = ρg ⋯ ①
By the definition of Bulk Modulus
K = dp / dρ/ρ
⇒ dp = Kdρ / ρ ⋯②
Substituting ② in ①
Kdρ / ρdh = ρg
⇒Kdρ / ρ 2 = g dh
⇒−K / ρ = g h + C
Given at h = 0, ρ = ρ0
Given at h = 0, ρ = ρ0 ⇒
−K/ ρ0 = C
⇒−K / ρ = gh − K / ρ0
K / ρ =K / ρ0 − gh
ρ0K / K − ρ0gh = ρ ⋯ ③
Substituting the same in ①
dp / dh =ρ0Kg / K − ρ0gh
Given, K = 2070 MN/m2
ρ0g = 10050 N/m3
∴ at h = 1500
p = 2070 ln ( 2070 × 106 / 2070 × 106 − 10050 × 1500)
p = 15.13 MPa
Most Upvoted Answer
What is the intensity of pressure (in MPa) in the ocean at a depth o...
Calculating Pressure Intensity in the Ocean
Given:
- Depth of the ocean: 1500 m
- Density of salt water at the free surface: 10050 N/m3
- Bulk modulus of elasticity of salt water (E): 2070 MN/m2
Formula:
The pressure intensity at a given depth in a fluid can be calculated using the formula:
Pressure Intensity = Density × Acceleration due to Gravity × Depth
Calculations:
1. Convert the given depth from meters to kilometers:
Depth = 1500 m ÷ 1000 = 1.5 km
2. Substitute the given values into the formula:
Pressure Intensity = 10050 N/m3 × 9.81 m/s2 × 1.5 km
3. Convert the pressure intensity to MPa:
Pressure Intensity = 10050 N/m3 × 9.81 m/s2 × 1.5 km ÷ 1000 MPa
Solution:
After performing the calculations, we find that the pressure intensity in the ocean at a depth of 1500 m is approximately 15.1 to 15.2 MPa.
Given:
- Depth of the ocean: 1500 m
- Density of salt water at the free surface: 10050 N/m3
- Bulk modulus of elasticity of salt water (E): 2070 MN/m2
Formula:
The pressure intensity at a given depth in a fluid can be calculated using the formula:
Pressure Intensity = Density × Acceleration due to Gravity × Depth
Calculations:
1. Convert the given depth from meters to kilometers:
Depth = 1500 m ÷ 1000 = 1.5 km
2. Substitute the given values into the formula:
Pressure Intensity = 10050 N/m3 × 9.81 m/s2 × 1.5 km
3. Convert the pressure intensity to MPa:
Pressure Intensity = 10050 N/m3 × 9.81 m/s2 × 1.5 km ÷ 1000 MPa
Solution:
After performing the calculations, we find that the pressure intensity in the ocean at a depth of 1500 m is approximately 15.1 to 15.2 MPa.
Attention Civil Engineering (CE) Students!
To make sure you are not studying endlessly, EduRev has designed Civil Engineering (CE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Civil Engineering (CE).
|
Explore Courses for Civil Engineering (CE) exam
|
|
Similar Civil Engineering (CE) Doubts
Top Courses for Civil Engineering (CE)View all
What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer?
Question Description
What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer?.
What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer?.
Solutions for What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE).
Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.
Here you can find the meaning of What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer?, a detailed solution for What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer? has been provided alongside types of What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.
|
|
Explore Courses for Civil Engineering (CE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup