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What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).
Correct answer is '15.1 to 15.2'. Can you explain this answer?
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What is the intensity of pressure (in MPa) in the ocean at a depth o...
By hydro-static law
dp / dh = ρg ⋯ ①
By the definition of Bulk Modulus
K = dp / dρ/ρ
⇒ dp = Kdρ / ρ ⋯②
Substituting ② in ①
Kdρ / ρdh = ρg
⇒Kdρ / ρ 2 = g dh
⇒−K / ρ = g h + C
Given at h = 0, ρ = ρ0
Given at h = 0, ρ = ρ0 ⇒
−K/ ρ0 = C
⇒−K / ρ = gh − K / ρ0
K / ρ =K / ρ0 − gh
ρ0K / K − ρ0gh = ρ ⋯ ③
Substituting the same in ①
dp / dh =ρ0Kg / K − ρ0gh
Given, K = 2070 MN/m2
ρ0g = 10050 N/m3
∴ at h = 1500
p = 2070 ln ( 2070 × 106 / 2070 × 106 − 10050 × 1500)
p = 15.13 MPa
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What is the intensity of pressure (in MPa) in the ocean at a depth o...
Calculating Pressure Intensity in the Ocean
Given:
- Depth of the ocean: 1500 m
- Density of salt water at the free surface: 10050 N/m3
- Bulk modulus of elasticity of salt water (E): 2070 MN/m2
Formula:
The pressure intensity at a given depth in a fluid can be calculated using the formula:
Pressure Intensity = Density × Acceleration due to Gravity × Depth
Calculations:
1. Convert the given depth from meters to kilometers:
Depth = 1500 m ÷ 1000 = 1.5 km
2. Substitute the given values into the formula:
Pressure Intensity = 10050 N/m3 × 9.81 m/s2 × 1.5 km
3. Convert the pressure intensity to MPa:
Pressure Intensity = 10050 N/m3 × 9.81 m/s2 × 1.5 km ÷ 1000 MPa
Solution:
After performing the calculations, we find that the pressure intensity in the ocean at a depth of 1500 m is approximately 15.1 to 15.2 MPa.
Given:
- Depth of the ocean: 1500 m
- Density of salt water at the free surface: 10050 N/m3
- Bulk modulus of elasticity of salt water (E): 2070 MN/m2
Formula:
The pressure intensity at a given depth in a fluid can be calculated using the formula:
Pressure Intensity = Density × Acceleration due to Gravity × Depth
Calculations:
1. Convert the given depth from meters to kilometers:
Depth = 1500 m ÷ 1000 = 1.5 km
2. Substitute the given values into the formula:
Pressure Intensity = 10050 N/m3 × 9.81 m/s2 × 1.5 km
3. Convert the pressure intensity to MPa:
Pressure Intensity = 10050 N/m3 × 9.81 m/s2 × 1.5 km ÷ 1000 MPa
Solution:
After performing the calculations, we find that the pressure intensity in the ocean at a depth of 1500 m is approximately 15.1 to 15.2 MPa.
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What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer?
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What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer?.
What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the intensity of pressure (in MPa) in the ocean at a depth of 1500 m. The salt water is compressible and weighs 10050 N/m3 at the free surface? E (bulk modulus of elasticity of salt water) = 2070 MN/m2 (constant).Correct answer is '15.1 to 15.2'. Can you explain this answer?.
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