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Let V = {p(x) : p(x) ≠ 0 and p(x) of degree 2} be a set of all non-zero polynomial in x of degree 2 is not a vector space, because ofa)V is not closed under additionb)V is not closed with respect to scalar multiplicationc)Identity element does not exists in V.d)Commutative property does not hold in VCorrect answer is option 'C'. Can you explain this answer? for Mathematics 2024 is part of Mathematics preparation. The Question and answers have been prepared according to the Mathematics exam syllabus. Information about Let V = {p(x) : p(x) ≠ 0 and p(x) of degree 2} be a set of all non-zero polynomial in x of degree 2 is not a vector space, because ofa)V is not closed under additionb)V is not closed with respect to scalar multiplicationc)Identity element does not exists in V.d)Commutative property does not hold in VCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mathematics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let V = {p(x) : p(x) ≠ 0 and p(x) of degree 2} be a set of all non-zero polynomial in x of degree 2 is not a vector space, because ofa)V is not closed under additionb)V is not closed with respect to scalar multiplicationc)Identity element does not exists in V.d)Commutative property does not hold in VCorrect answer is option 'C'. Can you explain this answer?.

Solutions for Let V = {p(x) : p(x) ≠ 0 and p(x) of degree 2} be a set of all non-zero polynomial in x of degree 2 is not a vector space, because ofa)V is not closed under additionb)V is not closed with respect to scalar multiplicationc)Identity element does not exists in V.d)Commutative property does not hold in VCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mathematics. Download more important topics, notes, lectures and mock test series for Mathematics Exam by signing up for free.

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