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An inclined tube manometer measures the gauge pressure ps of a system S (Fig.). The reservoir and tube diameters of the manometer are 50 mm and 5 mm respectively. The inclination angle of the tube is 30°. What will be the percentage error in measuring Ps if the reservoir deflection is neglected?
Correct answer is 'Range: 1.96 to 1.96'. Can you explain this answer?
Verified Answer
An inclined tube manometer measures the gauge pressure ps of a system...
Equating pressure values at 1 and 1′
P1 = P1′
P1 = ρg(h + R sin θ) ⋯ ①
By mass conservation Ah = aR
π 4 / D2 h = π 4 / d2R
h / R = d2 / D2
h / R = (5 / 50)2
h / R= 0.01
If h term is neglected in ① as h ≪ R
P1 ≃ ρgR sin θ
which will be an approximate value of P1
∴ Error = Exact − Approximate
% Error = Exact − Approximate / Exact × 100
% Error = ρg(h + R sin θ) − ρgR sin θ / ρg(h + R sin θ) × 100
% Error = h / h + R sin θ × 100
% Error = 1 / 1 +R / h sin θ × 100
% Error = 1 / 1 + 100 ×1 / 2 × 100
% Error = 1.96%
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Most Upvoted Answer
An inclined tube manometer measures the gauge pressure ps of a system...
Equating pressure values at 1 and 1′
P1 = P1′
P1 = ρg(h + R sin θ) ⋯ ①
By mass conservation Ah = aR
π 4 / D2 h = π 4 / d2R
h / R = d2 / D2
h / R = (5 / 50)2
h / R= 0.01
If h term is neglected in ① as h ≪ R
P1 ≃ ρgR sin θ
which will be an approximate value of P1
∴ Error = Exact − Approximate
% Error = Exact − Approximate / Exact × 100
% Error = ρg(h + R sin θ) − ρgR sin θ / ρg(h + R sin θ) × 100
% Error = h / h + R sin θ × 100
% Error = 1 / 1 +R / h sin θ × 100
% Error = 1 / 1 + 100 ×1 / 2 × 100
% Error = 1.96%
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Community Answer
An inclined tube manometer measures the gauge pressure ps of a system...
Equating pressure values at 1 and 1′
P1 = P1′
P1 = ρg(h + R sin θ) ⋯ ①
By mass conservation Ah = aR
π 4 / D2 h = π 4 / d2R
h / R = d2 / D2
h / R = (5 / 50)2
h / R= 0.01
If h term is neglected in ① as h ≪ R
P1 ≃ ρgR sin θ
which will be an approximate value of P1
∴ Error = Exact − Approximate
% Error = Exact − Approximate / Exact × 100
% Error = ρg(h + R sin θ) − ρgR sin θ / ρg(h + R sin θ) × 100
% Error = h / h + R sin θ × 100
% Error = 1 / 1 +R / h sin θ × 100
% Error = 1 / 1 + 100 ×1 / 2 × 100
% Error = 1.96%
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An inclined tube manometer measures the gauge pressure ps of a system S (Fig.). The reservoir and tube diameters of the manometer are 50 mm and 5 mm respectively. The inclination angle of the tube is 30°. What will be the percentage error in measuring Ps if the reservoir deflection is neglected?Correct answer is 'Range: 1.96 to 1.96'. Can you explain this answer?
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An inclined tube manometer measures the gauge pressure ps of a system S (Fig.). The reservoir and tube diameters of the manometer are 50 mm and 5 mm respectively. The inclination angle of the tube is 30°. What will be the percentage error in measuring Ps if the reservoir deflection is neglected?Correct answer is 'Range: 1.96 to 1.96'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about An inclined tube manometer measures the gauge pressure ps of a system S (Fig.). The reservoir and tube diameters of the manometer are 50 mm and 5 mm respectively. The inclination angle of the tube is 30°. What will be the percentage error in measuring Ps if the reservoir deflection is neglected?Correct answer is 'Range: 1.96 to 1.96'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An inclined tube manometer measures the gauge pressure ps of a system S (Fig.). The reservoir and tube diameters of the manometer are 50 mm and 5 mm respectively. The inclination angle of the tube is 30°. What will be the percentage error in measuring Ps if the reservoir deflection is neglected?Correct answer is 'Range: 1.96 to 1.96'. Can you explain this answer?.
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