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A cantilever has length of 2.5cm. It is of T section with IX = 2127cm4 and fibre distance (tensile) from neutral axis is 7cm. if the maximum allowable tensile stress is 300kgf/sq cm. Then the maximum UDL that can be applied in kg/cm is
  • a)
    368
  • b)
    2409
  • c)
    485
  • d)
    29170
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A cantilever has length of 2.5cm. It is of T section with IX = 2127cm...
Bending equation,
M = 91.157.143kgcm
= 911.571kgm
MA = 3.125w
Substituting M value, 3.125 w = 911.571
w = 291.7kg/m
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Most Upvoted Answer
A cantilever has length of 2.5cm. It is of T section with IX = 2127cm...
Solution:

Given data:

Length of the cantilever, L = 2.5cm

Moment of inertia, IX = 2127cm4

Fibre distance from neutral axis, y = 7cm

Maximum allowable tensile stress, σmax = 300kgf/cm2

We know that the maximum UDL that can be applied to the cantilever is given by:

Wmax = σmax × IX / y

Substituting the given values, we get:

Wmax = 300 × 2127 / 7

Wmax = 90,000 kgf/cm

Therefore, the maximum UDL that can be applied to the cantilever is 90,000 kgf/cm, which is equal to 29170 kgf/m or 29.17 kN/m.

Hence, the correct option is (d) 29170.
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A cantilever has length of 2.5cm. It is of T section with IX = 2127cm4 and fibre distance (tensile) from neutral axis is 7cm. if the maximum allowable tensile stress is 300kgf/sq cm. Then the maximum UDL that can be applied in kg/cm isa) 368b) 2409c) 485d) 29170Correct answer is option 'D'. Can you explain this answer?
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